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SSSSS [86.1K]
1 year ago
6

9. Find the volume of the triangular pyramid. (2pts)-10 mI9 m16 m

Mathematics
1 answer:
Makovka662 [10]1 year ago
4 0

Answer:

240 m³

Explanation:

The volume of a pyramid is equal to:

V=\frac{1}{3}\times B\times H

Where B is the area of the base and H is the height of the pyramid.

Then, the base of the pyramid is a triangle, so the area of a triangle is equal to:

B=\frac{b\times h}{2}

Where b is the base of the triangle and h is the height of the triangle. So, replacing b by 16 m and h by 9 m, we get:

B=\frac{16\times9}{2}=\frac{144}{2}=72m^2

Finally, replacing B by 72 m² and H by 10 m, we get that the volume of the pyramid is equal to:

V=\frac{1}{3}\times72\times10=\frac{1}{3}\times720=240m^3

Therefore, the volume is 240 m³

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Skewed to the left.

Step-by-step explanation:

The left side of the graph is at 2 and is 4 units from the middle at 6. The right side of the graph is at 9 and is 3 units from the middle. As such the graph is skewed left since it is a greater distance from the left to the center.

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3 years ago
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Anit [1.1K]

Answer:

show how you know  .. :D  good rhyme  

Step-by-step explanation:

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but one inch = 30 miles  ooh big park

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3 years ago
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2 years ago
Can someone help me with this problem ​
Alex_Xolod [135]

Answer:

<h2>A = 20</h2><h2>P = 6√10</h2>

Step-by-step explanation:

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d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A(-3, 0) , B(3, 2)

AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}

A(-3, 0), D(-2, -3)

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Substitute:

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P=2(AB+AD)

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3 years ago
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Since giving you the exact answer wouldn't help you learn anything, read this:

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