Question

Help would be nice, i’m out of school from covid

Answer 1

SOLUTION:

We are to pick from the given tiles the pairs that are associated with each functions.

Note that each of the pairs are of the form (x,y) coordinates.

(1)

$y=6^x$

The correct tiles for this function with explanation are given as follow;

$\begin{gathered} (1,6)\text{ } \\ y\text{ = 6 when x =1 } \\ y=6^x \\ 6=6^1 \\ \text{Correct} \end{gathered}$$\begin{gathered} (0,1) \\ y\text{ = 1 when x = 0} \\ y=6^x \\ 1=6^0 \\ \text{Correct} \end{gathered}$$\begin{gathered} (2,36) \\ y=36\text{ when x = 2} \\ y=6^x \\ 36=6^2 \\ \text{Correct} \end{gathered}$$\begin{gathered} (0.5,\sqrt[]{6)} \\ y\text{ = }\sqrt[]{6}\text{ when x = 0.5} \\ y=6^x \\ \sqrt[]{6}=6^{0.5} \\ \sqrt[]{6}=6^{\frac{1}{2}} \\ \sqrt[]{6}\text{ = }\sqrt[]{6} \\ \text{Correct} \end{gathered}$

For the first function, above tried tiles are the associated ones any other one different from those explained above are not associated with the fuction.

(2)

$y=\log _6x$

The correct tiles for this function are given as follow;

$(6,1),\text{ (1, 0), (36 ,2) and (}\sqrt[]{6\text{ }}\text{ , 0.5)}$

Let me explain or prove two out of the four tiles.

$\begin{gathered} (6,\text{ 1)} \\ y\text{ = 1 when x =6} \\ y=\log _6x \\ 1=\log _66 \\ \text{Correct} \end{gathered}$$\begin{gathered} (\sqrt[]{6},\text{ 0.5)} \\ y\text{ = 0.5 when x = }\sqrt[]{6} \\ y=\log _6x \\ 0.5\text{ =}\log _6\sqrt[]{6} \\ \frac{1}{2}=\log _66^{\frac{1}{2}} \\ \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\log _66 \\ \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\text{ x 1} \\ \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\text{ } \\ \\ \text{Correct} \end{gathered}$

You can also use the approach above to confirm the remaining two.