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mario62 [17]
2 years ago
7

Question 1

Mathematics
1 answer:
KengaRu [80]2 years ago
3 0

Answer: I x - 16ozI ≤ 0.4oz

Step-by-step explanation:

The weight is supposed to be exactly 16 oz.

But we can accept a maximum error of 0.4oz.

Now, if x is the weight of the sugar bag, the error can be calculated as:

E = x - 16oz

if x is larger than 16oz, we have E positive, which means that we have more sugar than 16oz

if x is smaller than 16 oz, we have E negative, which means that we are a little bit short of sugar in the bag.

Now, we know that the maximum error acceptable is 0.4 oz (negative or positive)

So we can write:

-0.4oz ≤ E ≤ 0.4oz

-0.4 ≤ x - 16oz ≤ 0.4oz

Now, if we apply absolute value to the error, we get:

I x - 16ozI ≤ 0.4oz

So the correct option is the fourth one (or the bottom one)

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miss Akunina [59]

Answer:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

Step-by-step explanation:

1st boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a

Equation:

y=ax^2 -2ax+c

The y-coordinate of the vertex:

y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1

Solve:

c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}

Parabola equation:

y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}

2nd boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0

Equation:

y=ax^2+c

The y-coordinate of the vertex:

y_v=a\cdot 0^2+c\Rightarrow c=-7

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-7\\ \\64a-7=1

Solve:

a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7

Parabola equation:

y=\dfrac{1}{8}x^2 -7

System of two equations:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

7 0
3 years ago
Read 2 more answers
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