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VikaD [51]
1 year ago
9

I need help with my pre-calculus homework, please show me how to solve them step by step if possible. The image of the problem i

s attached. This is parts A and B of the same question.

Mathematics
1 answer:
Anna [14]1 year ago
8 0

We know that the law of sines states that:

\frac{\sin\alpha}{a}=\frac{\sin\beta}{b}

For simplicity, let:

\beta=m\angle A_1BC

In triangle A1BC this leads to:

\begin{gathered} \frac{\sin31}{5}=\frac{\sin\beta}{6} \\ \sin\beta=\frac{6}{5}\sin31 \\ \beta=\sin^{-1}(\frac{6}{5}\sin31) \\ \beta=38.174 \end{gathered}

Therefore:

m\angle A_1BC=38.174

Now, triangle A2BC is isosceles which means that both the base angles are equal, since angle CA1B and A2A1B are supplementary we have:

m\angle CA_2B=180-38.174=141.826

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What does “more than” mean in math?
patriot [66]

Means if a number is bigger than other number.

5 0
1 year ago
Read 2 more answers
I NEED HELP PLEASE ! :(
denis-greek [22]

Answer:

4

Step-by-step explanation

because 256 is root of  4 raised to 4

so 4 root 4 is to 4 which is = to 4

hope it helped u i am new on brainly so counldnt write properly

if it helped u plzzz mark as brainliest

3 0
3 years ago
Suppose f and g are continuous functions such that g(6) = 6 and lim x → 6 [3f(x) + f(x)g(x)] = 45. Find f(6).
aleksandr82 [10.1K]
Since g(6)=6, and both functions are continuous, we have:

\lim_{x \to 6} [3f(x)+f(x)g(x)] = 45\\\\\lim_{x \to 6} [3f(x)+6f(x)] = 45\\\\lim_{x \to 6} [9f(x)] = 45\\\\9\cdot lim_{x \to 6} f(x) = 45\\\\lim_{x \to 6} f(x)=5


if a function is continuous at a point c, then lim_{x \to c} f(x)=f(c), 

that is, in a    c ∈  a continuous interval, f(c) and the limit of f as x approaches c are the same.


Thus, since lim_{x \to 6} f(x)=5, f(6) = 5


Answer: 5


7 0
3 years ago
What is y(x)+ab-5 I don’t get the problem
diamong [38]

Answer:

ab+xy−5

Step-by-step explanation:

yx+ab−5  = xy+ab+−5

Simplify-

ab+xy−5

6 0
2 years ago
the length of a rectangular garden is 3 m greater than the width. The area of the garden is 70m squared. find the dimensions of
Lerok [7]
A = l x w

so you know that the length is 3m longer than the width, so you could use a formula to represent that

w = l + 3

you then substitute the second equation into the first to solve for l

70 = l x (l +3)
70 = l^2 + 3l

you could then rearrange the formula and solve for l using the quadratic formula 

0 = l^2 + 3l - 70

l = -3 +- (square root (3)^2 - 4(1)(70)) / 2(1)
l = -3 +- (square root 9 + 280) / 2
l = -3 +- (square root 289) / 2
l = -3 +- 17 / 2

then you solve for the two seperate roots

l = -3 + 17 /2
l = 14 / 2
l = 7

or 

l = -3 - 17 / 2
l = -20 / 2
l = -10

since a length cannot be negative, this root is not viable. therefore l = 7

to solve for w you would use

w = l + 3
w = 7 + 3
w = 10 

hope this helps! if you did not understand a step or concept please let me know!
4 0
3 years ago
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