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sertanlavr [38]
1 year ago
13

a student that weighs 436 n is standing on a scale in an elevator and notices that the scale reads 498 n. from this information,

the elevator is:
Physics
1 answer:
mash [69]1 year ago
7 0

The elevator has constant acceleration upward

Given that a student that weighs 436 N is standing on a scale in an elevator and notices that the scale reads 498 N.

The formula of force can be derived from the Newton's second law of motion, which states that the force exerted by any object equals mass times the acceleration of that object i.e., F = ma

Net force = mg + ma

498 = 436 + ma

62 = 436 a/ 9.8

a = (62 x 9.8) / 436

a = 1.39 m/s²

Hence, it is clear that the elevator has constant acceleration upward.

Learn more about Elevator force here

brainly.com/question/4289588

#SPJ4

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A 4.67-g bullet is moving horizontally with a velocity of +357 m/s, where the sign + indicates that it is moving to the right (s
Leni [432]

Answer:

(a)0.531m/s

(b)0.00169

Explanation:

We are given that

Mass of bullet, m=4.67 g=4.67\times 10^{-3} kg

1 kg =1000 g

Speed of bullet, v=357m/s

Mass of block 1,m_1=1177g=1.177kg

Mass of block 2,m_2=1626 g=1.626 kg

Velocity of block 1,v_1=0.681m/s

(a)

Let velocity of the second block  after the bullet imbeds itself=v2

Using conservation of momentum

Initial momentum=Final momentum

mv=m_1v_1+(m+m_2)v_2

4.67\times 10^{-3}\times 357+1.177(0)+1.626(0)=1.177\times 0.681+(4.67\times 10^{-3}+1.626)v_2

1.66719=0.801537+1.63067v_2

1.66719-0.801537=1.63067v_2

0.865653=1.63067v_2

v_2=\frac{0.865653}{1.63067}

v_2=0.531m/s

Hence, the  velocity of the second block after the bullet imbeds itself=0.531m/s

(b)Initial kinetic energy before collision

K_i=\frac{1}{2}mv^2

k_i=\frac{1}{2}(4.67\times 10^{-3}\times (357)^2)

k_i=297.59 J

Final kinetic energy after collision

K_f=\frac{1}{2}m_1v^2_1+\frac{1}{2}(m+m_2)v^2_2

K_f=\frac{1}{2}(1.177)(0.681)^2+\frac{1}{2}(4.67\times 10^{-3}+1.626)(0.531)^2

K_f=0.5028 J

Now, he ratio of the total kinetic energy after the collision to that before the collision

=\frac{k_f}{k_i}=\frac{0.5028}{297.59}

=0.00169

5 0
3 years ago
Which is considered computer storage
Korolek [52]

Answer:

Second Option

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Hope this helps.

8 0
3 years ago
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A coaxial cable consists of a solid inner cylindrical conductor of radius 2 mm and an outer cylindrical shell of inner radius 3
4vir4ik [10]

Answer:

d) 1.2 mT

Explanation:

Here we want to find the magnitude of the magnetic field at a distance of 2.5 mm from the axis of the coaxial cable.

First of all, we observe that:

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I = 15 A

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Therefore, the net magnetic field is just given by the internal conductor. The magnetic field produced by a wire is given by

B=\frac{\mu_0 I}{2\pi r}

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\mu_0 is the vacuum permeability

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r = 2.5 mm = 0.0025 m is the distance from the axis at which we want to calculate the field

Substituting, we find:

B=\frac{(4\pi\cdot 10^{-7})(15)}{2\pi(0.0025)}=1.2\cdot 10^{-3}T = 1.2 mT

8 0
3 years ago
What happens to infrared radiation when it comes to contact wih a shiny suface
Ksivusya [100]

If a surface looks "shiny" to you, that's because it reflects all
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3 years ago
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This equation is used to calculate the properties of a gas under nonideal conditions.
goblinko [34]

Answer:

Van der Waal's equation

Explanation:

The Van der Waal's equation is use to calculate the properties of a gas under nonideal or real gases conditions.

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Here P, V ,T ,n and R have usual meaning as in the ideal gas equation

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