2 years ago

All mutations are favorable and increase the ability for the

Physics

1 answer:

masya89 [10]2 years ago

3 0

False sometimes you get a bad mutation

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High-energy particles are observed in laboratories by photographing the tracks they leave in certain detectors; the length of th

murzikaleks [220]

Answer:

Lifetime = 4.928 x 10^-32 s

Explanation:

(1 / v2 – 1 / c2) x2 = T2

T2 = (1/ 297900000 – 1 / 90000000000000000) 0.0000013225

T2 = (3.357 x 10^-9 x 1.11 x 10^-17) 1.3225 x 10^-6

T2 = (3.726 x 10^-26) 1.3225 x 10^-6 = 4.928 x 10^-32 s

4 0

2 years ago

Bare free charges do not remain stationary when close together. To illustrate this, calculate the acceleration of two isolated p

Marta_Voda [28]

Answer:

Acceleration, $a=9.91\times 10^{15}\ m/s^2$

Explanation:

It is given that,

Separation between the protons, $r=3.73\ nm=3.73\times 10^{-9}\ m$

Charge on protons, $q=1.6\times 10^{-19}\ C$

Mass of protons, $m=1.67\times 10^{-27}\ kg$

We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :

$ma=\dfrac{kq^2}{r^2}$

$a=\dfrac{kq^2}{mr^2}$

$a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.67\times 10^{-27}\times (3.73\times 10^{-9})^2}$

$a=9.91\times 10^{15}\ m/s^2$

So, the acceleration of two isolated protons is $9.91\times 10^{15}\ m/s^2$ . Hence, this is the required solution.

3 0

3 years ago

Circle the letter of each expression that has four significant figures. A. 1.25 x 10^4 B. 12.51 C. 0.0125 D. 0.1255

Andreyy89

Answer:

letter B

none zero digit are significant figures

3 0

3 years ago

Fronts are termed by the temperature of the air mass that overtakes another air mass. A. True B. False

Vikki [24]

A. True
if cold air is replacing warm air it is a cold front and vice versa.

6 0

2 years ago

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Scientists want to place a telescope on the moon to improve their view of distant planets. The telescope weighs 200 pounds on Ea

Maru [420]

Answer:

33,02 lb

Explanation:

g_m ≈ 1,62 m/s2

g ≈ 9,81 m/s2

m = 200 lb

m_m = m * g_m / m = 200 * 1,62 / 9,81 = 33,02 lb

7 0

3 years ago

Read 2 more answers