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Keith_Richards [23]
3 years ago
6

How could you create an investigation to determine the pitch of this wave?

Physics
1 answer:
Musya8 [376]3 years ago
6 0

Answer:

In order to make a sound wave have a higher pitch you increase the frequency.

In order to increase the volume of a sound wave, you have to increase the amplitude.

Hope this helps!

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A 120.0 kg crate is placed on a 15.00°
Citrus2011 [14]

F = 2820.1 N

Explanation:

Let the (+)x-axis be up along the slope. The component of the weight of the crate along the slope is -mgsin15° (pointing down the slope). The force that keeps the crate from sliding is F. Therefore, we can write Newton's 2nd law along the x-axis as

Fnet = ma = 0 (a = 0 no sliding)

= F - mgsin15°

= 0

or

F = mgsin15°

= (120 kg)(9.8 m/s^2)sin15°

= 2820.1 N

7 0
3 years ago
You are using an 8 th order low-pass filter. Determine the roll-off achievable in the stop band, in dB/dec, and determine the ph
Andreas93 [3]

Answer: The complexity of filter is the order of the filter. Greater the order of the filter, more efficient the filter is. Roll of value of one filter is 20dB/dec. So the roll-off value of 8th order filter is 160dB/dec. 8th order filter is more efficient than the second order low-pass filter.

4 0
3 years ago
In fission processes, which of the following statements is true? The total number of protons and the total number of neutrons bo
Amiraneli [1.4K]

Answer: A. The total number of protons and the total number of neutrons both remain the same.

Explanation:

Nuclear fission is the process in which a large nucleus splits into two smaller nuclei with the release of energy. In other words, fission is the process in which a nucleus is divided into two or more fragments, and neutrons and energy are released.

7 0
3 years ago
What is the cell emf for the concentrations given? Express your answer using two significant figures.
alisha [4.7K]

Complete Question

A  voltaic cell is  constructed with two Zn^{2+}- Zn electrodes. The  two cell compartment have  [Zn^{2+}] =  1.6 \ M and  [Zn^{2+}] =  2.00*10^{-2} \  M respectively.

What is the cell emf for the concentrations given? Express your answer using two significant figures

Answer:

The value is   E =  0.06 V

Explanation:

Generally from the question we are told that

   The  concentration of [Zn^{2+}] at the cathode is  [Zn^{2+}]_a =  1.6 \ M

    The  concentration of [Zn^{2+}] at the anode is [Zn^{2+}]_c =  2.00*10^{-2} \  M

Generally the the cell emf for the concentration is mathematically represented as

     E =  E^o - \frac{0.0591}{2} log\frac{[Zn^{2+}]a}{ [Zn^{2+}]c}

Generally the E^ois the standard emf of a cell, the value is  0 V

So

      E =  0  -  \frac{0.0591}{2}  * log[\frac{ 2.00*10^{-2}}{1.6} ]

=>      E =  0.06 V

4 0
3 years ago
Answer pls. This is for People like me with this Question . Help!!! Question 3 of 20 What happens to the electric force between
Dafna1 [17]

Answer:

It increases twice the original

8 0
3 years ago
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