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3 years ago

How could you create an investigation to determine the pitch of this wave?

Physics

1 answer:

Musya8 [376]3 years ago

6 0

Answer:

In order to make a sound wave have a higher pitch you increase the frequency.

In order to increase the volume of a sound wave, you have to increase the amplitude.

Hope this helps!

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The critical angle for a beam of light passing from water into air is 48.8°. this means that all light rays with an angle of inc

Len [333]

totally internally reflected

8 0

3 years ago

Read 2 more answers

In a "worst-case" design scenario, a 2000 kg elevator with broken cables is falling at 4.00 m/s when it first contacts a cushion

Leno4ka [110]

Answer:

4 m/s²

Explanation:

When the elevator is 1 m below point of contact , compression will be 1 m.

Restoring force in the spring will be 10600 N. Friction force of 17000N will also act in upward direction . The weight of 2000 x 9.8 N will act downwards

Force in down ward direction = 2000 x 9.8

= 19600 N

Force in upward direction

= 10600 + 17000

= 27600 N

Net force in upward direction

= 27600 - 19600

= 8000 N

Acceleration in upward direction

= 8000 / 2000

= 4 m/s²

5 0

3 years ago

A mover hoists a 200 kg piano from the ground to a height of 10 m using a single pulley. What was the change in the pianos energ

RideAnS [48]

P.E= Mass x gravity x height (standard gravity = 10m/s approaximately)
= 200x10x10= 20000j (D)

7 0

3 years ago

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Which of these charges is experiencing the electric field with the largest magnitude? A 2C charge acted on by a 4 N electric for

Pavlova-9 [17]

Answer:

The highest electric field is experienced by a 2 C charge acted on by a 6 N electric force. Its magnitude is 3 N.

Explanation:

The formula for electric field is given as:

E = F/q

where,

E = Electric field

F = Electric Force

q = Charge Experiencing Force

Now, we apply this formula to all the cases given in question.

A) A 2C charge acted on by a 4 N electric force

F = 4 N

q = 2 C

Therefore,

E = 4 N/2 C = 2 N/C

B) A 3 C charge acted on by a 5 N electric force

F = 5 N

q = 3 C

Therefore,

E = 5 N/3 C = 1.67 N/C

C) A 4 C charge acted on by a 6 N electric force

F = 6 N

q = 4 C

Therefore,

E = 6 N/4 C = 1.5 N/C

D) A 2 C charge acted on by a 6 N electric force

F = 6 N

q = 2 C

Therefore,

E = 6 N/2 C = 3 N/C

E) A 3 C charge acted on by a 3 N electric force

F = 3 N

q = 3 C

Therefore,

E = 3 N/3 C = 1 N/C

F) A 4 C charge acted on by a 2 N electric force

F = 2 N

q = 4 C

Therefore,

E = 2 N/4 C = 0.5 N/C

The highest field is 3 N, which is found in part D.

A 2 C charge acted on by a 6 N electric force

3 0

3 years ago

How do you think the total resistance of a parallel circuit is calculated?

igomit [66]

Let's consider two resistors only for simplicity. When the resistors are connected in parallel, the potential difference on each resistor is the same, and it is equal to the voltage of the battery, V:
$V_1 = V_2 = V$ (1)
Instead, the current splits in the two resistors:
$I=I_1 + I_2$ (2)
where I is the current in the circuit, I1 and I2 are the currents in the two resistors.
By using Ohm's law, we can rewrite (2) as
$\frac{V}{R_{eq}} = \frac{V_1}{R_1}+ \frac{V_2}{R_2}$ (3)
where $R_{eq}$ is the equivalent resistance of the circuit. But we also said that
$V_1 = V_2 = V$
So we can rewrite (3) as
$\frac{V}{R_{eq}}= \frac{V}{R_1}+ \frac{V}{R_2}$
which becomes
$\frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}$

So, the equivalent resistance of the parallel of n resistors is given by
$\frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}+...+ \frac{1}{R_n}$

6 0

2 years ago