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irinina [24]
1 year ago
11

What is the surface area of this cone?Use ≈ 3.14 and round your answer to thenearest hundredth.10 m3 msquare metersSubmit

Mathematics
1 answer:
Natali5045456 [20]1 year ago
3 0

Given:

There is a cone given with radius 3 m and slant height 10 m

Required:

We need to find the surface area of given cone

Explanation:

surface area of cone is

SA=\pi r(l+r)=3.14*3(10+3)\approx122.46\text{ m}^3

Final answer:

Surface area of cone is 122.46 cubic meter

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Find the whole quantity if 5 percent of it is 500​
liq [111]

Answer:

10,000

Step-by-step explanation:

500/0.05= 10,000

You take the amount you are given divided by the decimal form of the percentage you are given to find the answer.  It's a reverse from the way you find 5% of 10,000.

0.05=5%

Check your work: 10,000*5%= 500

5 0
3 years ago
Translate to an algebraic expression: the sum of x and twice y
never [62]

Answer:

x+2y

20 character minimum

3 0
4 years ago
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A student performed the following steps to find the solution to the question x^2 - 2x - 15 = 0. Where did the student go wrong?
nataly862011 [7]

Answer:

D  In step 3

Step-by-step explanation:

Given polynomial:  x² - 2x - 15 = 0

Step 1:  factor the polynomial ⇒ (x + 3)(x - 5) = 0

Step 2:  x + 3 = 0  and  x - 5 = 0

Step 3:  x = -3  and x = 5

x - 5 = 0

Add 5 to both sides:

⇒ x - 5 + 5 = 0 + 5

⇒ x = 5

7 0
2 years ago
Please help me to solve this . Thank you so much .
worty [1.4K]

Answer:

a) N

b) L

c) area I

d) area II

e) area VI

Step-by-step explanation:

a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.

b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.

c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.

d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.

e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.

5 0
3 years ago
An equo equila Teral Traingle has
Murljashka [212]

Answer:

Step-by-step explanation:

Given parameters:

Dimensions of the equilateral triangle = 6.2cm

Unknown:

Perimeter = ?

Solution:

The perimeter of the triangle is the sum of all its sides;

  Perimeter = 3(L) for an equilateral triangle;

 Perimeter  = 3(6.2) = 18.6cm

to the nearest mm = 19.0cm

6 0
4 years ago
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