In APQR, the measure of ZR=90°, RQ = 55, PR = 48, and QP = 73. What ratio represents the sine of ZQ?

Mathematics

1 answer:

Irina18 [472]1 year ago

5 0

To find the angle Q we can us the sin law so:

$\frac{\sin (Q)}{48}=\frac{\sin (90)}{73}$

So we can solve for Q so:

$\begin{gathered} \sin (Q)=\frac{48}{73} \\ \measuredangle Q=\sin ^{-1}(0.6) \\ \measuredangle Q=36.87 \end{gathered}$

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