Question

In APQR, the measure of ZR=90°, RQ = 55, PR = 48, and QP = 73. What ratio represents the sine of ZQ?

Answer 1

To find the angle Q we can us the sin law so:

$\frac{\sin (Q)}{48}=\frac{\sin (90)}{73}$

So we can solve for Q so:

$\begin{gathered} \sin (Q)=\frac{48}{73} \\ \measuredangle Q=\sin ^{-1}(0.6) \\ \measuredangle Q=36.87 \end{gathered}$