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1 year ago

Give the structure of the principal organic product formed by free-radical bromination of 2,2,4−trimethylpentane.

1 answer:

7 0

the principal organic product formed by free-radical bromination of 2,2,4−trimethylpentane is 2-bromo-2,4,4-trimethylpentane.

what is free radical halogenation?

A substitution reaction in which a hydrogen atom is replaced with a halogen atom, via a free radical reaction mechanism. when this reaction is carrid out by bromine radical, it is called free radicle bromination. When bromine ( $Br{2}$ ) treated with light (hν) it comes to homolytic cleavage of the Br-Br bond and give rise to bromine radicles.

free-radical bromination of 2,2,4−trimethylpentane

Bromination of an alkane includes the substitution of a bromine atom for a hydrogen atom. The following stages will be taken by 2,2,4-trimethylpentane during this reaction:

Initiation reaction: The production of a bromine free radical requires the initiation of heat or light.

$Br - Br$ ⇒ $2Br$ ·

Propagation: This reaction relies heavily on hydrogen. This reaction is impossible if hydrogen is not present. Because tertiary free radicals are more stable than secondary and primary free radicals, they are favoured in this reaction.

Termination: The remaining free radical of bromide reacts with the tertiary free radical of 2,2,4-trimethylpentane to form 2-bromo-2,4,4-trimethylpentane.

the principal organic product formed by free-radical bromination of 2,2,4−trimethylpentane is 2-bromo-2,4,4-trimethylpentane.

To know more about free radical halogenation, check out:

brainly.com/question/13046867

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What is the difference between Renewable Energy and Non renewable Energy? Which one is better for the environment and why? Also

goblinko [34]

Answer:

The difference between them is that renewable energy is something that can be used practically and not run out. Non-renewable energy has a limited supply.

Explanation:

Renewable energy is better for the environment as it is not something that takes millions of years to form, as some non-renewable energy sources are.

Brainliest please! :>

6 0

2 years ago

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Consider 100.0 g samples of two different compounds consisting only of carbon and oxygen. One compound contains 27.2 g of carbon

Pani-rosa [81]

Answer: The ratio of carbon in both the compounds is 1 : 2

Explanation:

Law of multiple proportions states that when two elements combine to form two or more compounds in more than one proportion. The mass of one element that combine with a given mass of the other element are present in the ratios of small whole number. For Example: $Cu_2O\text{ and }CuO$

For Sample 1:

Total mass of sample = 100 g

Mass of carbon = 27.2 g

Mass of oxygen = (100 - 27.7) = 72.8 g

To formulate the formula of the compound, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{27.2g}{12g/mole}=2.26moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{72.8g}{16g/mole}=4.55moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 2.26 moles.

For Carbon = $\frac{2.26}{2.26}=1$

For Oxygen = $\frac{4.55}{2.26}=2.01\approx 2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 2

Hence, the formula for sample 1 is $CO_2$

For Sample 2:

Total mass of sample = 100 g

Mass of carbon = 42.9 g

Mass of oxygen = (100 - 42.9) = 57.1 g

To formulate the formula of the compound, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{42.9g}{12g/mole}=3.57moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{57.1g}{16g/mole}=3.57moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.57 moles.

For Carbon = $\frac{3.57}{3.57}=1$

For Oxygen = $\frac{3.57}{3.57}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 1

Hence, the formula for sample 1 is $CO$

In the given samples, we need to fix the ratio of oxygen atoms.

So, in sample one, the atom ratio of oxygen and carbon is 2 : 1.

Thus, for 1 atom of oxygen, the atoms of carbon required will be = $\frac{1}{2}\times 1=\frac{1}{2}$

Now, taking the ratio of carbon atoms in both the samples, we get:

$C_1:C_2=\frac{1}{2}:1=1:2$

Hence, the ratio of carbon in both the compounds is 1 : 2

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3 years ago

The majority of the world’s water is stored in?

aniked [119]

Answer:

Ocean

Explanation:

97 percent of the water in the world is in the ocean.

The 3 percent of freshwater is located in lakes, streams, glaciers, and can be found underground.

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3 years ago

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arsen [322]

The first one would be the best answer

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3 years ago

Mrs. DeFord wanted to know whether or not her students would do better on a quiz if she promised them candy.

marta [7]

Answer:

a.) Independent Variable: # of candy bars promised to each group

[ The Independent Varaiable is what you change in the experiment]

b.) Dependent Variable: Quiz Scores

[ The Dependent Variable is what you're testing in the experiment; what the experiment should affect]

c.) Constant(s): Same Quiz, same number of gender kids in each group, same age kids in each group, same ability, and same background. [and same time, I'm assuming.]

[Constants are what you keep the same in the experiment; what you're not changing.]

d.) Testable Question: Will promising kids candy make them do better on tests and quizzes? [or something along this lines of this]

[The Testable Question is what you're trying to find out in the experiment]

e.) Hypothesis: The more candy the students were promised, the better results Mrs. DeFord would get from them.

[The Hypothesis is what the person performing the experiment expects will happen; an educated guess]

f. Formal Conclusion: Data shows that kids who were promised more candy had a better average than kids who were promised less candy/none. Mrs. DeFord's hypothesis was correct, since she assumed the more candy the students were promised, the better they would do on the quiz.

[The Formal Conclusion is what you have learned from the experiment, and wether or not the hypothesis was correct or not.]

I hope this helps! :)

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3 years ago

Read 2 more answers