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inn [45]
3 years ago
8

If 63.4 J of heat are added to a sample

Chemistry
1 answer:
jeka57 [31]3 years ago
3 0

Answer:

dt = 4.32°C

Explanation:

<u>Given the following data;</u>

Mass = 16.33g

Quantity of heat, Q = 63.4J

Specific heat capacity = 0.899 J/g °C

To find the temperature change;

Heat capacity is given by the formula;

Q = mcdt

Where;

  • Q represents the heat capacity or quantity of heat.
  • m represents the mass of an object.
  • c represents the specific heat capacity of water.
  • dt represents the change in temperature.

Making dt the subject of formula;

dt = \frac {Q}{mc}

Substituting into the equation, we have;

dt = \frac {63.4}{16.33*0.899}

dt = \frac {63.4}{14.6807}

dt = 4.32°C

Therefore, the change in temperature for this aluminum is equal to 4.32°C.

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