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s2008m [1.1K]
1 year ago
8

Did you use the counting principle ? Describe a time in your life where you could have used the counting principle to help you c

ount total options.

Mathematics
1 answer:
Natali [406]1 year ago
4 0

Yes, I use the counting principle in my day-to-day life.

I have used the counting principle to overcome to perform the following task in day to day life:

1 ) In order to schedule my school timings and study timetable choices I have used the counting principle.

2 ) I have 7 T-shirts and 5 pants in my wardrobe for daily wear. I use the counting principle to set up different combinations and decide a particular pair of shirt-pant combination for a day.

3 ) I have playing cards with me. On weekends when I play with my cards, I use the counting principle to decide which card is to be drawn first so as to win the game.

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The sum of three consecutive odd integers is -75. What is the smallest number
pashok25 [27]

Answer:

-27

Step-by-step explanation:

First, let's call the smallest number: n

Then, the next two consecutive odd numbers would be:

n+2 and n+4 (this is because it's only odd numbers so we add 2)

We know the sum of these is −75 so we can write this equation and solve for n:

n + (n + 2) + (n + 4) = -75

n + n + 2 + n + 4 = -75

n + n + n + 2 + 4 = -75

n + n + n + 6 = -75

1n + 1n + 1n + 6 = -75

3n + 6 = -75        Subtract 6 from each side, which cancels the 6 on the left.

3n + 6 - 6 = -75 - 6

3n = -75 - 6

3n = -81       Divide each side by 3

3n/3 = -81/3

n = -81/3

n = -27

n + 2 = -27 + 2 = -25

n + 4 = -27 + 4 = -23

The 3 consecutive odd integers would be:

-27, -25, -23

Let's check our work:

-27 + -25 + -23 = -75    We are correct!

The smallest number is -27

3 0
3 years ago
Your class is holdinga fundraiser for a local charity after the first week your class raised 1/8 goal after the second week your
n200080 [17]

Answer: \dfrac{19}{40}

Step-by-step explanation:

Given: Fraction of goal raised on first day = \dfrac{1}{8}

Fraction of goal raised after second day  = \dfrac35

Now , Fraction of goal raised on second day = Fraction of goal raised after second day  - Fraction of goal raised on first day

=\dfrac35-\dfrac18\\\\=\dfrac{24-5}{40}\\\\=\dfrac{19}{40}

Required fraction = \dfrac{19}{40}

7 0
3 years ago
The fence around anne's garden forms a right triangle. the length of one leg is 5 meters, and the hypotenuse is 13 meters. what
Roman55 [17]
The length of the other section is 12
5 0
4 years ago
Read 2 more answers
5. If the perimeter of the rectangle is 110cm, what is the length?
Elza [17]
Algebraic eq:
2(13) + 2(x+1) = 110

x= 41

width= 42
7 0
3 years ago
Two terms of a geometric sequence are given. Find the first five terms. Please help asap
Zepler [3.9K]

Answer:

4, 8, 16, 32, 64

Step-by-step explanation:

The nth term of a geometric sequence is

a_{n} = a₁(r)^{n-1}

Given

a₇ = 256 and a₁₀ = 2048 , then

a₁ r^{6} = 256 → (1)

a₁ r^{9} = 2048 → (2)

Divide (2) by (1)

\frac{a_{1}r^{9}  }{a_{1}r^{6}  } = \frac{2048}{256}

r³ = 8 ( take the cube root of both sides )

r = \sqrt[3]{8} = 2

Substitute r = 2 into (1)

a₁ × 2^{6} = 256

a₁ × 64 = 256 ( divide both sides by 64 )

a₁ = 4

Then

a₁ = 4

a₂ = 2a₁ = 2 × 4 = 8

a₃ = 2a₂ = 2 × 8 = 16

a₄ = 2a₃ = 2 × 16 = 32

a₅ = 2a₄ = 2 × 32 = 64

7 0
3 years ago
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