Answer:
-27
Step-by-step explanation:
First, let's call the smallest number: n
Then, the next two consecutive odd numbers would be:
n+2 and n+4 (this is because it's only odd numbers so we add 2)
We know the sum of these is −75 so we can write this equation and solve for n:
n + (n + 2) + (n + 4) = -75
n + n + 2 + n + 4 = -75
n + n + n + 2 + 4 = -75
n + n + n + 6 = -75
1n + 1n + 1n + 6 = -75
3n + 6 = -75 Subtract 6 from each side, which cancels the 6 on the left.
3n + 6 - 6 = -75 - 6
3n = -75 - 6
3n = -81 Divide each side by 3
3n/3 = -81/3
n = -81/3
n = -27
n + 2 = -27 + 2 = -25
n + 4 = -27 + 4 = -23
The 3 consecutive odd integers would be:
-27, -25, -23
Let's check our work:
-27 + -25 + -23 = -75 We are correct!
The smallest number is -27
Answer: 
Step-by-step explanation:
Given: Fraction of goal raised on first day = 
Fraction of goal raised after second day = 
Now , Fraction of goal raised on second day = Fraction of goal raised after second day - Fraction of goal raised on first day

Required fraction =
Algebraic eq:
2(13) + 2(x+1) = 110
x= 41
width= 42
Answer:
4, 8, 16, 32, 64
Step-by-step explanation:
The nth term of a geometric sequence is
= a₁
Given
a₇ = 256 and a₁₀ = 2048 , then
a₁
= 256 → (1)
a₁
= 2048 → (2)
Divide (2) by (1)
= 
r³ = 8 ( take the cube root of both sides )
r =
= 2
Substitute r = 2 into (1)
a₁ ×
= 256
a₁ × 64 = 256 ( divide both sides by 64 )
a₁ = 4
Then
a₁ = 4
a₂ = 2a₁ = 2 × 4 = 8
a₃ = 2a₂ = 2 × 8 = 16
a₄ = 2a₃ = 2 × 16 = 32
a₅ = 2a₄ = 2 × 32 = 64