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mr_godi [17]
1 year ago
5

Hi im really confused:

Physics
1 answer:
Vitek1552 [10]1 year ago
3 0

The energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ

U =  c_{p} m ΔT

U = Energy

c_{p} = Specific heat

m = Mass

ΔT = Change in temperature

ρ = Density

V = Volume

ρ = 1000 g / m³ (Dry air )

c_{p} = 1 J / g K

ΔT = 5 °C

V = 4 * 4 * 3

V = 48 m³

m = ρ V

m = 1000 * 48

m = 48000 g

U = 1 * 48000 * 7

U = 336000 J

U = 336 kJ

Therefore, the energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ

To know more about energy required to raise temperature

brainly.com/question/12372041

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The table below describes some features of methods used to generate electricity. Name method 4.
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Answer:

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Explanation:

Because of flooding of water, we can assume that the electricity was generated by Water which is known as Hydroelectricity.

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A 1800-kg Jeep travels along a straight 500-m portion of highway (from A to B) at a constant speed of 10 m/s. At B, the Jeep enc
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2 years ago
A beam of white light enters a prism of crown glass (n = 1.5) from air (n = 1.00). Once inside, the colors in the light disperse
eduard

Answer:

= 2.33

Explanation:

.According to snell's law:

n1sin i = n2sin r ,

where n1 is refractive index of the medium in which incident ray is travelling, n2 is the refractive index of the medium in which refracted ray is travelling,

i is angle of incidence,

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Given that,

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So,

1*sin 51 = n2 sin 19.5  

=> n2 = sin51 / sin19.5

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7 0
3 years ago
If an element is a semi-conductor, which classification correctly describes it?
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What is the volume of an object that has a density of 65g/cm3 and a mass of 130g.
lora16 [44]

Density <em>ρ</em> is mass <em>m</em> per unit volume <em>v</em>, or

<em>ρ</em> = <em>m</em> / <em>v</em>

Solving for <em>v</em> gives

<em>v</em> = <em>m</em> / <em>ρ</em>

So the given object has a volume of

<em>v</em> = (130 g) / (65 g/cm³) = 2 cm³

5 0
3 years ago
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