Answer:
Explanation:
Consider another special case in which the inclined plane is vertical (θ=π/2). In this case, for what value of m1 would the acceleration of the two blocks be equal to zero
F - Force
T = Tension
m = mass
a = acceleration
g = gravitational force
Let the given Normal on block 2 = N
and ![N = m_2 g \cos \theta](https://tex.z-dn.net/?f=N%20%3D%20m_2%20g%20%5Ccos%20%5Ctheta)
and the tension in the given string is said to be ![T = m_2 g \sin \theta](https://tex.z-dn.net/?f=T%20%3D%20m_2%20g%20%5Csin%20%5Ctheta)
When the acceleration ![a=\frac{F}{m_1}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7BF%7D%7Bm_1%7D)
for the said block 1.
It will definite be zero only when Force is zero , F=0.
Here by Force, F
I refer net force on block 1.
Now we know
![F = m_1g-T.](https://tex.z-dn.net/?f=F%20%3D%20m_1g-T.)
It is known that if the said
,
then Tension
,
Now making !["F = m_1g - m_2g"](https://tex.z-dn.net/?f=%22F%20%3D%20m_1g%20-%20m_2g%22)
So If we are to make Force equal to zero
![F=0 => m_1g = m_2g \ or \ m_1 = m_2](https://tex.z-dn.net/?f=F%3D0%20%3D%3E%20m_1g%20%3D%20m_2g%20%5C%20or%20%5C%20m_1%20%3D%20m_2)
In general, surface tension decreases when temperature increases because cohesive forces decrease with an increase of molecular thermal activity. The influence of the surrounding environment is due to the adhesive action of liquid molecules that they have at the interface.
Explanation:
(a)
Critical angle is the angle at the angle of refraction is 90°. After the critical angle, no refraction takes place.
Using Snell's law as:
Where,
is the angle of incidence
is the angle of refraction = 90°
is the refractive index of the refraction medium
is the refractive index of the incidence medium
Thus,
The formula for the calculation of critical angle is:
Where,
is the critical angle
(b)
No it cannot occur. It only occur when the light ray bends away from the normal which means that when it travels from denser to rarer medium.