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Thepotemich [5.8K]
1 year ago
13

What the name for the phenomenon of inducing voltage by changing the magnetic field around a conductor?

Physics
1 answer:
8090 [49]1 year ago
8 0

The phenomenon of inducing voltage by changing the magnetic field around a conductor will be Electromagnetic Induction. Option B is correct.

<h3>What is the Faraday law of electromagnetic induction?</h3>

According to Faraday's law of electromagnetic induction, the rate of change of magnetic flux link with the coil is responsible for generating emf in the coil to result in the flow of amount of current .

So in order to increase the current, we need to increase the EMF;

so we can increase it by;

1) Increasing the number of turns

2) Increase the area of the loop

3) By moving the magnet faster

Hence, option B is correct.

To learn more about Faraday law of electromagnetic induction:

brainly.com/question/13369951

#SPJ1

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I need help if you can help me to get 10 points.
Alinara [238K]

Answer:

It allows the reader to feel more connected to her purpose

Explanation:

If Cooper is using personal examples for her argument, she is allowing the reader see more of her point of view, which can also lead them to feel connected to her purpose

6 0
3 years ago
Read 2 more answers
Explain ALL THREE of Newton’s Laws in your own words.
Svet_ta [14]

Explanation:

(1) Every object moves in a straight line unless acted upon by a force. (2) The acceleration of an object is directly proportional to the net force exerted and inversely proportional to the object's mass. (3) For every action, there is an equal and opposite reaction.

5 0
2 years ago
Enem 2003 embalagens longa vida brick​
tresset_1 [31]

Answer:

Jyftfufhfucyf fyfycyxycydyd

Explanation:

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3 0
2 years ago
If the gas inside the flask in the above exercise is cooled so that its pressure is reduced to a value of 715.7 torr, what will
evablogger [386]

Answer:

(a) 49.0 mm

Explanation:

#First we need to calculate the height of the mercury arm:

Reduced pressure is 715.7torr, Initial Pressure is 797.3torr, Required pressure is:

P_g_a_s=P_a_t_m+P_h\\  

The difference in the two arms will give the pressure difference between the gas placed in the flask attached to an open-end mercury manometer.

P_g_a_s=P_a_t_m+P_h\\797.3=P_a_t_m+(136.4mm-103.8mm)\\P_a_t_m=764.7mm\\\\h_t_o_t_a_l=136.4mm+103.8mm=240.2mm\\\\P_g_a_s=P_a_t_m+\bigtriangleup h\\\bigtriangleup h=P_g_a_s-P_a_t_m\\\\\bigtriangleup h=715.7mm-764.7mm\\=-49mm

Hence the height of the mercury in the arm is 49.00mm

4 0
3 years ago
A kite 40 ft above the ground moves horizontally at a constant speed of 10 ft/s, with a child, holding the ball of kite string,
Lorico [155]

Answer:

 v = 27.28 m /s, θ = 63.9º

Explanation:

For this exercise we can approximate the movement to a projectile launch, let's analyze the situation.

* We must find the horizontal speed, for this we will find the descent time and the horizontal distance

* We look for the vertical speed

At the highest point the speed is horizontal

Let's find the time it takes for the kite to reach the ground

             y = y₀ + v_{oy} t - ½ g t²

             0 =y₀ + 0 -1/2 gt²

             t = \sqrt{ \frac{2y_o}{g} }

             t = √(2 40/32)

             t = 2.5 s

to find the horizontal velocity we must know the horizontal distance, let's use trigonometry

          sin θ = y / l

          θ = sin⁻¹1 y / l

          θ = sin⁻¹ 40/50

          θ = 53.1º

therefore the horizontal distance is

          x = l cos 53.1

          x = 50cos 53.1

          x = 30 m

let's use the equation

          x = v₀ₓ t

          v₀ₓ = x / t

          v₀ₓ = 30 / 2.5

          v₀ₓ = 12 m / s

we look for the vertical component of the velocity

          v_y = v_{oy} - g t

          v_y = 0 - g t

          v_y = - 9.8 2.5

          v_y = -24.5 m / s

the negative sign indicates that the speed is directed downwards, because it is the arrival point, as they indicate that there is no friction, the exit speed is the same, worse with the opposite sign

We already have the two components of the velocity, let's use the Pythagorean theorem to find the modulus

          v = \sqrt{v_x^2 + v_y^2}

          v = \sqrt{12^2 + 24.5^2}

          v = 27.28 m /s

we use trigonometry for the angle

          tan θ = v_y / vₓ

          θ = tan⁻¹ v_y / vₓ

          θ = tan⁻¹ 24.5 / 12

          θ = 63.9º

4 0
2 years ago
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