1. The chemical reaction produced by Carlo's fire is exergonic because energy is "going out". As the reaction proceeds, entropy increases as the energy stored in the dry wood and leaves are used up as fuel to create the fire which produces low quality light and warmth.
2. This reaction is a classic example of an exothermic reaction. Exothermic reactions are characterized with the presence of heat and light in the products. Combustion reactions are always exothermic in nature.
3. Catalyst are substances that are used to speed up reactions by lowering the activation requirement. Catalysts aren't consumed in the reaction and can still be chemically retrieved afterwards. In this situation, the leaves cannot be retrieved after the reaction ends. The leaves speed up the heating of the wood but it does not behave as a catalyst.
Less because the ramp is letting off force but i does depend on the way you are going on the ramp
Answer:
440hz
Explanation:
saxophone a plays at 430hz and a frequency of 5 beats per second can be heard so saxophone b is playing at a frequency 10hz louder than saxophone A making it 440hz
Answer:
The value is ![T_c = 12 .1 ^oC](https://tex.z-dn.net/?f=T_c%20%20%3D%20%2012%20.1%20%5EoC)
Explanation:
From the question we are told that
The mass of the ice cube is ![m_i = 7.50 *10^{-3} \ kg](https://tex.z-dn.net/?f=m_i%20%20%3D%20%207.50%20%2A10%5E%7B-3%7D%20%5C%20%20kg)
The temperature of the ice cube is
The mass of the copper cube is ![m_c = 0.540 \ kg](https://tex.z-dn.net/?f=m_c%20%20%3D%20%200.540%20%5C%20%20kg)
The final temperature of both substance is ![T_f = 0^oC](https://tex.z-dn.net/?f=T_f%20%20%3D%20%200%5EoC)
Generally form the law of thermal energy conservation,
The heat lost by the copper cube = heat gained by the ice cube
Generally the heat lost by the copper cube is mathematically represented as
![Q = m_c * c_c * [T_c - T_f ]](https://tex.z-dn.net/?f=Q%20%3D%20%20m_c%20%20%2A%20%20c_c%20%2A%20%20%5BT_c%20%20-%20%20T_f%20%5D)
The specific heat of copper is ![c_c = 385J/kg \cdot ^oC](https://tex.z-dn.net/?f=c_c%20%20%3D%20385J%2Fkg%20%5Ccdot%20%20%5EoC)
Generally the heat gained by the ice cube is mathematically represented as
![Q_1 = m_i * L](https://tex.z-dn.net/?f=Q_1%20%3D%20%20m_i%20%2A%20L%20)
Here L is the latent heat of fusion of the ice with value ![L = 3.34 * 10^{5} J/kg](https://tex.z-dn.net/?f=L%20%20%3D%20%203.34%20%2A%2010%5E%7B5%7D%20J%2Fkg)
So
![Q_1 = 7.50 *10^{-3} * 3.34 * 10^{5}](https://tex.z-dn.net/?f=Q_1%20%3D%20%207.50%20%2A10%5E%7B-3%7D%20%2A%203.34%20%2A%2010%5E%7B5%7D%20%20%20)
=>
So
=> ![T_c = 12 .1 ^oC](https://tex.z-dn.net/?f=T_c%20%20%3D%20%2012%20.1%20%5EoC)