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3 years ago

Write the general equation for the circle that passes through the points: (0, 0) (6, 0) (0, - 8)

Mathematics

1 answer:

Ksivusya [100]3 years ago

5 0

<span> (x-h)^2+(y-k)^2=r^2

</span>(x-3)^2+(y+4)^2=25

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If you mean missing angle, it would be 129.

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There are 60 girls and 45 boys who want to participate in a co-ed basketball tournament. if each team must have the same number

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Answer:

15 teams, 4 girls and 3 boys on each team.

Step-by-step explanation:

What's the greatest common multiple of 60 and 45? It's 15.

This is the greatest number of teams that can be formed.

60/15 = 4; thus, there will be 4 girls on each team.

45/15 = 3; thus, 3 boys on each team

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1. On the last 5 quizzes, Marco has earned a total of 21 out of 25 possible points. If he has a perfect

Nonamiya [84]

The number of points Marco needs to bring his average up to 90% is 15points.

If there's a possible 25 possible points, and Marco has taken 5 quizzes;

Evidently, each quiz has weighs 5 points.

Mathematically;

$\frac{21 + 5x}{5(5 + x)} \times 100\% = \frac{90}{100}$

2100 + 500x = 2250 + 450x

50x = 150

x = 3.

Therefore, he needs 5x points = 15 points to bring his average up to 90%.

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2 years ago

A quality control expert wants to estimate the proportion of defective components that are being manufactured by his company. A

tigry1 [53]

Answer:

A sample of 1032 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

A sample of 300 components showed that 20 were defective.

This means that $\pi = \frac{20}{300} = 0.0667$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

How large a sample is needed to estimate the true proportion of defective components to within 2.5 percentage points with 99% confidence?

A sample of n is needed.

n is found when M = 0.025. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.025 = 2.575\sqrt{\frac{0.0667*0.9333}{n}}$

$0.02\sqrt{n} = 2.575\sqrt{0.0667*0.9333}$

$\sqrt{n} = \frac{2.575\sqrt{0.0667*0.9333}}{0.02}$

$(\sqrt{n})^2 = (\frac{2.575\sqrt{0.0667*0.9333}}{0.02})^2$

$n = 1031.9$

Rounding up

A sample of 1032 is needed.

6 0

2 years ago