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timama [110]
1 year ago
8

14 (OM) Radicals and Estimation (2 pts) Without a calculator, estimate the radical and explain how you estimated. Then using a c

alculator and compare your estimation and the approximation.Example:(1 + 2sqrt(5))/4Estimate without a calculator: boxed 1,3Explanation: I estimate (l + 2sqrt(5))/4 to be approximately 1.3, because...√5 is between sqrt(4) and sqrt(9) , but closer to sqrt(4) (since 5 is closer to 4 than it is to 9). Since sqrt(4) is 2. sqrt(5) is probably something like 2.1 or 2.2. Filling 2.1, In the expression and simplifying, we have this:l+2^ * 2.1 4 = 1+4.2 4 = 5.2 4 =1.3 So, I expect the number (2sqrt(5) + 1)/4 to be close to 1.3. [Note: The goal here is NOT to be exact! This problem will be graded on explanations of your reasoning.]a)NO CALCULATOR(1; ) 3 - sqrt(38)Estimate without a calculatorExplanation:b) CALCULATOR ALLOWED (1 pt) For the same problem given in part " a^ * above, use a calculator toapproximate, rounding to the hundredths. Use correct notation for approximation. Compare your estimation and the approximation. Does your estimation seem to be correct? Why or why not?

Mathematics
1 answer:
Irina-Kira [14]1 year ago
5 0

Q) Without a calculator, we must estimate the value of the following expression:

3-\sqrt[]{38}.

A) I estimate 3 - √38 to be approximately -3.2.

First, we estimate the value of √38. √38 is between √36 and √49, but close to √36 (since 38 is closer to 4 than it is to 9). Since √36 is 6, √38 is probably something like 6.1 or 6.2. Filling 6.2 in the expression and simplifying, we have this:

3-6.2=-3.2.

So, I expect the number 3 - √38 to be close to -3.2.

Using a calculator we find that: 3 - √38 ≅ -3.16, which it is approximately the result that we found.

Answer

Without a calculator we find that 3 - √38 ≅ -3.2.

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Alright, so 3f-g=4 and f+2g=5. 
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Multiplying the first equation by 2 and adding it to the second, we get 7f=13 and by dividing both sides by 7 we get f=13/7. Since f+2g=5, then we can plug 13/7 in for f to get 13/7+2g=5. Next, we subtract 13/7 from both sides to get 2g=3+1/7=22/7 (since 3*7=21 and 21+1=22). DIviding both sides by 2, we get 22/14=g. Plugging that into f/39g, we get (13/7)/(22*39/14)
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21−=2(2−)=2cos(−1)+2 sin(−1)

−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2

Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.

complex-numbers

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edited Mar 6 '17 at 4:38

Richard Ambler

1,52199 silver badges1616 bronze badges

asked Mar 6 '17 at 3:34

14wml

23122 silver badges99 bronze badges

Add a comment

1 Answer

1

No. It is not true that =cos()+sin(). Notice that

1=1≠cos()+sin(),

for example consider this at =0.

As a hint for figuring this out, notice that

+=ln(+)

then recall your rules for logarithms to get this to the form (+)ln().

8 0
3 years ago
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