Answer:
5 english students in each team
Step-by-step explanation:
So there are multiple ways to do this, you could do trial and error or you could factor out common numbers between the two.
Through trial and error, the lowest possible number of groups that could be divided between the number of students whilst still being able to maintain a whole # was 16 groups
- 128 math students ÷16 groups = 8 math students/group
- 80 english students ÷ 16 groups = 5 english students/group
The other way to solve this is to factor out common numbers between the two:
Answer:
750 < p < 1500
Step-by-step explanation:
The total cost of the affair for p attendees is ...
750 +2.25p
The average cost is that number divided by p. The answer choices suggest that "between" means that the cost per person cannot be 2.75 or 3.25. Applying the limits to the average cost, we get ...
2.75 < (750 +2.25p)/p < 3.25
2.75 < 750/p + 2.25 < 3.25 . . . . . . . . separating the fraction parts
0.50 < 750/p < 1.00 . . . . . . . . . . . . . . subtract 2.25
2 > p/750 > 1 . . . . . . . . . . . . . . . . . . . . . take the reciprocal*
1500 > p > 750 . . . . . . . . matches choice 4
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* Taking the reciprocals of numbers with the same sign reverses their order:
2 < 3 but 1/2 > 1/3
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An alternate approach to the solution would be to multiply by p:
0.50p < 750 < 1.00p
To solve this requires it be made into two inequalities:
0.50p < 750 ⇒ p < 1500
and
750 < 1.00p ⇒ 750 < p
Then these would need to be recombined to form the answer:
750 < p < 1500
Answer:
no it's an acute triangle
Step-by-step explanation:
why? because any angle below 90 degrees is considered an acute triangle which in your case 20,24, and 36 are all very far from being a right triangle
Graph the inequality by finding the boundary line, then shading the appropriate area.
y>2x-5
Answer:
x y
0 0 - this is the y intercept
1 -4
2 -8
3 -12
4 -16
Step-by-step explanation:
