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dsp73
1 year ago
11

A flowerpot falls from a window sill 36.5 m

Physics
1 answer:
hram777 [196]1 year ago
7 0

When a flowerpot falls from a window sill 36.5 m

above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.

From Newton's third equation of motion,

v^2 = u^2 + 2gh

where,

h is the height of the object or body from ground

u is the initial velocity of the body or object

v is the final velocity of the body or object

g is the acceleration due to gravity

Now, as we know that

Flowerpot is at rest. So, u = 0

g = 9.81m/s^2

h = 36.5m

By substituting all the values, we get

v^2 = 2 × 9.81 × 36.5

= 716.13

v = 26.7m/s

Thus, we concluded that when a flowerpot falls from a window sill 36.5 m

above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.

learn more about Newton's equation of law of motion:

brainly.com/question/8898885

#SPJ9

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Answer: I believe it’s .25 m/s

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7 0
3 years ago
A force does work on an object if a component of the force is
IrinaK [193]

Answer:

A force does work on an object if a component of the force is parallel to the displacement of the object.

Explanation:

Work, a measurement of energy is said to be done when a force applied to an object results in the movement of that object to a certain distance and direction. Force is the act of push or pulls occurs on an object as a result of the interaction between that object with another one and displacement is the distance and direction covered by that object as a result of the force applied on it.

The work done (W) by a constant force (F) is equal to the product of the force in the direction of displacement of the object and the distance (d) moved by the object i.e., W = F * d.

The angle between the displacement and the force is θ, then the work done, W = Fd cos θ  ........ (1)

Positive work - Force acts in the same direction with respect to the displacement of the object. Here, θ is zero, so cos θ i.e., cos 0 is 1. Therefore, from the equation (1), W = Fd (i.e., work done by the force is positive).

Negative work - Force acts in the opposite direction with respect to the displacement of the object.  Here, θ is 180°, so cos θ i.e., cos 180° is -1. Therefore, from the equation (1), W = -Fd (i.e., work done by the force is negative).

If a force is applied to an object and it does not move, then the work done is zero i.e., W = F * 0 = 0. Also, if the force and displacement are at right angle to each other, then θ is 90°. Therefore, from the equation (1), W = 0 since cos 90° is zero.

7 0
4 years ago
Which of the following is a key assumption of the scientific method
lesantik [10]

Answer:

Though you have not gave the choices, I do believe it is “testing”

Explanation:

3 0
3 years ago
Susie rides down and to the right on a slide for a total displacement of -3m at an angle of 45 degrees above the ground. What wa
Svetlanka [38]

Susie's vertical displacement is 2.1 m

Explanation:

In order to solve this problem, we have to resolve the displacement vector along the vertical direction.

The vertical component of a vector is given by:

v_y = v sin \theta

where

v is the magnitude of the vector

\theta is the angle between the direction of the vector and the horizontal

Therefore, the vertical  component of the displacement in this problem is given by

d_y = d sin \theta

where

d = 3 m is the magnitude of the displacement

\theta=45^{\circ} is the angle between the  displacement and the horizontal

Substituting, we find

d_y = (3)(sin 45^{\circ})=2.1 m

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6 0
4 years ago
Please help! Giving 20 points!!
MrMuchimi

Answer:

Explanation:

Remark

This is a momentum question. Both cars are sitting still (v1 and v2 are both 0) to start with). When the spring is sprung), they both move but in opposite directions.

Let us say that v4 is minus.

Equation

0 = m3*v3 - m4* v4

Givens

m3 = 1750 kg

m4 = 1000 kg

v3 = 4 m/s

Solution

m3*4m/s - m4*x = 0

1750 * 4 - 1000*x = 0

1750 * 4 = 1000x

7000 = 1000 x

7000/1000 = x

x = 7 m/s

7 0
3 years ago
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