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dsp73
1 year ago
11

A flowerpot falls from a window sill 36.5 m

Physics
1 answer:
hram777 [196]1 year ago
7 0

When a flowerpot falls from a window sill 36.5 m

above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.

From Newton's third equation of motion,

v^2 = u^2 + 2gh

where,

h is the height of the object or body from ground

u is the initial velocity of the body or object

v is the final velocity of the body or object

g is the acceleration due to gravity

Now, as we know that

Flowerpot is at rest. So, u = 0

g = 9.81m/s^2

h = 36.5m

By substituting all the values, we get

v^2 = 2 × 9.81 × 36.5

= 716.13

v = 26.7m/s

Thus, we concluded that when a flowerpot falls from a window sill 36.5 m

above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.

learn more about Newton's equation of law of motion:

brainly.com/question/8898885

#SPJ9

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Answer:

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Explanation:

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Explanation:

The information was found on:

https://msnucleus.org/membership/html/k-6/rc/rocks/3/rcr3_1a.html

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2 years ago
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A hot cube of iron was heated up using 1500 J of thermal energy and was placed in a beaker of water. Before it was heated, the i
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Answer:

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Make c the subject of the equation

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From the question,

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Substitute these values into equation 2

c = 1500/[0.133(45-20)]

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