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3 years ago

During the fission reaction shown, how did the target nucleus change ?

Physics

1 answer:

Zarrin [17]3 years ago

5 0

Answer:

A. The target nucleus split into two nuclei, each with fewer nucleons than the original.

Explanation:

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What separates musical theater from other dance styles?

Rus_ich [418]

Answer: Musical theater is like acting in a musical.

Explanation: Other dance styles don't involve singing.

7 0

2 years ago

PLEASE HELP ASAP!! DUE IN AN HOUR :’))!!

miskamm [114]

Answer: The object moves with constant velocity

Explanation:

In this velocity vs time graph we're dealing with Ap physics or regents physics. If we look at the slope we can see it is constant or not changing. Even so lets check the other answers and prove them wrong

The objects speed increases: This is wrong because the line shows a steady 5m/s with no change

The object is in free fall: If the object was in freefall the speed would be increasing as a result of acceleration due to gravity

The object moves with a constant speed: This seems to be the case since the slope or line doesn't change at all

The object stays at rest: Can't be right because the object is at a speed of 5m/s so we know its moving at least

The objects speed decreases: Again the line isn't going up or down so we can't say speed increases or decreases

4 0

2 years ago

AYUDA!!!!!

ZanzabumX [31]

Answer:

a) El valor de la densidad es 0.79 $\frac{g}{cm^{3} }$ o 790 $\frac{g}{cm^{3} }$

b) El peso especifico es 7749.9 $\frac{N}{m^{3} }$

Explanation:

a) La densidad se define como la propiedad que tiene la materia, ya sean sólidos, líquidos o gases, para comprimirse en un espacio determinado. En otras palabras, la densidad es una magnitud que permite medir la cantidad de masa que hay en determinado volumen de una sustancia. Entonces, la expresión para el cálculo de la densidad es el cociente entre la masa de un cuerpo y el volumen que ocupa:

$d=\frac{m}{V}$

En este caso:

masa= 237 g= 0,237 kg (siendo 1000 g= 1 kg)
volumen= 300 cm³= 0,0003 m³ (siendo 1 cm³= 0,000001 m³)

Reemplazando:

$d=\frac{237 g}{300cm^{3} }$ → d=0.79 $\frac{g}{cm^{3} }$

$d=\frac{0,237 kg}{0,0003m^{3} }$ → d=790 $\frac{g}{cm^{3} }$

El valor de la densidad es 0.79 $\frac{g}{cm^{3} }$ o 790 $\frac{g}{cm^{3} }$

b) El peso específico es la relación existente entre el peso y el volumen que ocupa una sustancia en el espacio.

Entonces, en este caso, siendo el peso:

P= m*g= 0,237 kg* 9,81 $\frac{m}{s^{2} }$ = 2,32497 N

el peso especifico es calculado como:

$Pe=\frac{Peso}{Volumen}= \frac{2,32497N}{0,0003 m^{3} }$

Pe= 7749.9 $\frac{N}{m^{3} }$

El peso especifico es 7749.9 $\frac{N}{m^{3} }$

8 0

3 years ago

A mass M of 3.80E-1 kg slides inside a hoop of radius R=1.10 m with negligible friction. When M is at the top, it has a speed of

Vikentia [17]

Answer:

N = 26.59 N

Explanation:

given,

mass = 0.38 kg

radius of the hoop = 1.10 m

speed = 5.35 m/s

force = ?

now,

$\dfrac{1}{2}mv_t^2 + mg(2R) = \dfrac{1}{2}mv^2 + mgR(1-cos \theta)$

$mv^2 = mv_t^2 + 2mgR(1 + cos \theta)$

we know that,

$N - mgcos \theta = \dfrac{mv^2}{R}$

$N - mgcos \theta = \dfrac{mv_t^2 + 2mgR(1 + cos \theta)}{R}$

$N - mgcos \theta = \dfrac{mv_t^2 }{R}+ 2mg(1 + cos \theta)$

$N = \dfrac{mv_t^2 }{R}+ 2mg + 3mgcos \theta)$

$N = \dfrac{0.38\times 5.35^2 }{1.1}+ 2\times 0.38\times 9.8 + 3\times 0.38 \times 9.8 cos 34^0)$

N = 26.59 N

3 0

3 years ago

An object of mass 2kg raised to a height 10m possess potential energy of 200J. What is the kinetic energy and potential energy a

Shtirlitz [24]

Explanation:

${\bold{\sf{\underline{Understanding \: the \: concept}}}}$

✠ This question says that there is an object and its mass is 2 kg ; it's raised to a height 10 m and possess potential energy of 200 J. Now this question ask us to find the kinetic energy and the potential energy at a height 4 metre.

$\bold{↬{ }}$ ${\bold{\sf{\underline{Given \: that}}}}$