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3 years ago

I'll give the brainliest!

Physics

1 answer:

Vaselesa [24]3 years ago

8 0

Answer:

Explanation:

1. Althea Gibson

2. Nathon Green

3. jeff carter

4 conused

5.Norm Duke- At 18

Hope this helps!!

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A spaceship from a friendly, extragalactic planet flies toward Earth at 0.201 times the speed of light and shines a powerful las

bagirrra123 [75]

Answer:

The wavelength of observed light on earth is 568.5 nm

Explanation:

Given that,

Velocity of spaceship $v= 0.201c$

Wavelength of laser $\lambda= 697\ nm$

We need to calculate the wavelength of observed light on earth

Using formula of wavelength

$\lambda_{0}=\lambda_{e}\times\sqrt{\dfrac{1-\dfrac{v}{c}}{1+\dfrac{v}{c}}}$

$\lambda_{0}=697\times10^{-9}\times\sqrt{\dfrac{1-\dfrac{0.201 c}{c}}{1+\dfrac{0.201c}{c}}}$

$\lambda_{0}=697\times10^{-9}\times\sqrt{\dfrac{1-0.201}{1+0.201}}$

$\lambda=5.685\times10^{-7}\ m$

$\lambda=568.5\times10^{-9}\ m$

$\lambda=568.5\ nm$

Hence, The wavelength of observed light on earth is 568.5 nm

8 0

4 years ago

The outer layer of cable on a cable reel is 16.2 cm from the center of the reel. The reel is initially stationary and can rotate

ahrayia [7]

Answer:

B. w=12.68rad/s

C. α=3.52rad/s^2

Explanation:

We can solve this problem by taking into account that (as in the uniformly accelerated motion)

$\theta=\omega_{0}t+\frac{1}{2}\alpha t^{2}\\\theta = \frac{s}{r}$ ( 1 )

where w0 is the initial angular speed, α is the angular acceleration, s is the arc length and r is the radius.

In this case s=3.7m, r=16.2cm=0.162m, t=3.6s and w0=0. Hence, by using the equations (1) we have

$\theta=\frac{3.7m}{0.162m}=22.83rad$

$22.83rad=\frac{1}{2}\alpha (3.6s)^2\\\\\alpha=2\frac{(22.83rad)}{3.6^2s}=3.52\frac{rad}{s^2}$

to calculate the angular speed w we can use $\alpha=\frac{\omega _{f}-\omega _{i}}{t _{f}-t _{i}}\\\\\omega_{f}=\alpha t_{f}=(3.52\frac{rad}{s^2})(3.6)=12.68\frac{rad}{s}$

Thus, wf=12.68rad/s

C) We can use our result in B)

$\alpha=3.52\frac{rad}{s^2}$

I hope this is useful for you

regards

3 0

3 years ago

Read 2 more answers

A stretched rubber band has ___________ energy. a. elastic kinetic energy b. gravitational potential energy c. elastic potential

densk [106]

Answer: Option (c) is the correct answer.

Explanation:

An elastic object is defined as the object that is able to retain its shape when a force is applied on it.

For example, when we pull a rubber band then it stretches and when we withdraw the force applied on it then it retain its shape.

As we know that potential energy is the energy obtained by an object due to its position.

So, when we stretch a rubber band then it will have elastic potential energy as position of the rubber band is changing and since, it will retain it shape hence it has elastic potential energy.

Thus, we can conclude that a stretched rubber band has elastic potential energy.

3 0

4 years ago

serious [3.7K]

<span>1 pound is equal to .454 kilograms.
115 pounds equals
115 x .454 kilograms = 52.163 kg.

The total dose is equal to the dose per kilograms multiplied by the total mass in kilograms.

6.00mg/kg x 52.163kg = 312.978mg.

The total dose is 313.0 mg</span>

3 0

3 years ago

Name two possible ways in wivh fossils can be dated and define them <br>

Vikentia [17]

Answer:

There are two main methods determining a fossils age, relative dating and absolute dating. Relative dating is used to determine a fossils approximate age by comparing it to similar rocks and fossils of known ages.

Mark me with a crown

6 0

3 years ago

Read 2 more answers