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Natali [406]
3 years ago
12

I'll give the brainliest!

Physics
1 answer:
Vaselesa [24]3 years ago
8 0

Answer:

Explanation:

1. Althea Gibson

2. Nathon Green

3. jeff carter

4 conused

5.Norm Duke- At 18

          Hope this helps!!

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During a 40-mile trip, Marla traveled at an average speed of x miles per hour for the first y miles of the trip and at an averag
Ilya [14]

Answer:

\dfrac{32+0.2y}{40}

Explanation:

Total =40 miles.

y miles at x miles/hr.

40- y miles at 1.25 x miles/hr.\

We know that

Distance = time x velocity

For y miles

Lets time taken to cover y miles is t

y = x t

t=y/x                -----------1

For 40- y

Lets time taken to cover 40- y is t'

40- y = 1.25 x t'  

t'=(40-y)/1.25x           -----------2

By adding both equation

t+t'=y/x  + (40-y)/1.25x

t+t'=(32+0.2y)/x

Now lets time T taken by Marla if she will travel at x miles per hr for entire trip.

40 = x T

T=40/x

So

\dfrac{t+t'}{T}=\dfrac{32+0.2y}{40}

To find numerical value of above expression we have to know the value of y.

8 0
4 years ago
How much time does it take for a spinning baseball with an angular speed of 38 rad/s to rotate through 15 degrees
Nadusha1986 [10]

Answer:

the time of motion of the ball is 6.89 ms.

Explanation:

Given;

angular speed, ω = 38 rad/s

angular distance, θ = 15 degrees

Angular distance in radian;

\theta = 15^0 \times\frac{2\pi \ rad}{360^0} = 0.2618 \ rad

Time of motion is calculated as;

time = \frac{angular \ distance}{angular \ speed} \\\\t= \frac{\theta}{\omega} = \frac{0.2618 \ rad}{38 \ rad/s} \\\\t = 6.89 \ \times 10^{-3} \ s\\\\t = 6.89 \ ms

Therefore, the time of motion of the ball is 6.89 ms.

3 0
3 years ago
A box is sliding along a frictionless surface and gets to a ramp. Disregarding friction, how fast should the box be going on the
levacccp [35]

This is amazing.  When you read the quest ion, you wouldn't think there's enough information there to find an answer.  But there is !

-- When the block is sliding along the flat surface, its kinetic energy is (1/2)(Mass·v²).

-- When it's 2.5m up the ramp and stops, its potential energy is (2.5m)·(Mass·g).

-- If there's no friction anywhere, these energies are equal.

(1/2)(Mass·v²)  =  (2.5m)·(Mass·g)

(v²/2) = (2.5m) · g

v² = 5m · g

v² = 49 m²/s²

<em>v = 7 m/s  </em>(B)

9 0
3 years ago
Read 2 more answers
What are the factors affecting gravitational force?​
oee [108]
  • Answer:
  • Distance between objects
  • Mass of objects
  • Force of gravitational field

6 0
4 years ago
I WILL MARK YOU TOP IF YOU HELP ME I NEED THIS ASAP!!!!
Pachacha [2.7K]
The basketballs and racquetball eventually stopped bouncing due to the first law. the first law states that an object at rest will stay at rest unless acted upon by an external force. this means that once the 2 balls lose friction, they will remain at rest until acted upon by an external force. once the 2 balls lose friction(energy), they come to a complete stop.
6 0
3 years ago
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