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Ira Lisetskai [31]
1 year ago
10

1. You invest $2500 with annual interest rate of 4%. How much money will you have after 5 years?Use the following formula:A = P(

1 + r)Show your work here:Choose the correct answer$2952S29325314253042

Mathematics
1 answer:
Yuki888 [10]1 year ago
8 0

$ 3042

Explanation

we need to use the formula:

\begin{gathered} A=P(1+r)^t \\ \text{where} \\ \text{ P is the principal} \\ r\text{ is the rate ( in decimal)} \\ t\text{ is the time} \end{gathered}

Step 1

a)let

\begin{gathered} P=2500 \\ r=\text{ 4\% =}\frac{4}{100}=0.04 \\ r=0.04 \\ t=5\text{ ( years)} \end{gathered}

b) now, replace

\begin{gathered} A=P(1+r)^t \\ A=2500(1+0.04)^5 \\ A=2500(1.04)^5 \\ A=2500(1.2166) \\ A=3041.63 \\ \text{rounded} \\ A=3042 \end{gathered}

therefore, the answer is

$ 3042

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Step-by-step explanation:

The numerator, 11^{18}, is equivalent to eighteen "11" multiplied together:

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On the other hand, the denominator, 11^{3}, is equivalent to three "11" multiplied with one another:

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Dividing 11^{18} by 11^{3} would eliminate three "11" from the numerator:

\begin{aligned}& \frac{11^{18}}{11^{3}} \\ =\; & \frac{(11 \times 11 \times 11) \times \overbrace{11 \times \cdots \times 11}^{\text{$(18 - 3)$ in total}}}{(11 \times 11 \times 11)} \\ =\; & \overbrace{11 \times \cdots \times 11}^{\text{$15$ in total}} \\ =\; & 11^{15}\end{aligned}.

In general, dividing an expression by y^{b} (y \ne 0) is equivalent to multiplying that expression by y^{-b}.

For example, in this question, dividing 11^{18} by 11^{3} would be equivalent to multiplying 11^{18}\! by 11^{-3}. In other words:

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