Trish is correct because whatever number starts the tree equals 48 anyway. The numbers that matters is if you follow through when factoring out the whole tree of 48.
The probability that the sum of Michelle's rolls is 4 is 0.083
∴ P(A)=0.083
Step-by-step explanation:
Given that Michelle is rolling two six-sided dice, numbered one through six.
To find the probability that the sum of her rolls is 4:
∴ n(s)=36
Let P(A) be the probability that the sum of her rolls is 4
Then the possible rolls with sums of 4 can be written as
n(A)=3
The probability that the sum of her rolls is 4 is given by
=0.083
∴ P(A)=0.083
∴ the probability that the sum of Michelle's rolls is 4 is 0.083
-please give brainliest if correct!
DE. AB, is going up BC, isn't decreasing or increasing. CD, isn't decreasing or increasing. Therefore your answer is DE.
There are several ways two triangles can be congruent.
<em> congruent by SAS</em>
<em> congruent by corresponding theorem</em>
In
and
(see attachment), we have the following observations
--- Because O is the midpoint of line segment AD
--- Because O is the midpoint of line segment BC
---- Because vertical angles are congruent
---- Because vertical angles are congruent
Using the SAS (<em>side-angle-side</em>) postulate, we have:
![\mathbf{AC = BD}](https://tex.z-dn.net/?f=%5Cmathbf%7BAC%20%3D%20BD%7D)
Using corresponding theorem,
---- i.e. both triangles are congruent
The above congruence equation is true because:
- <em>2 sides of both triangles are congruent</em>
- <em>1 angle each of both triangles is equal</em>
- <em>Corresponding angles are equal</em>
See attachment
Read more about congruence triangles at:
brainly.com/question/20517835
Answer:
(x,y) right arrow (negative x , y)
Step-by-step explanation:
Mathematically, when we reflect a point over the x-axis; we have a result
The result is that the x- coordinate of the point reflected takes up a negative value
so what we have here is that;
(x,y) becomes (-x,y) once reflected over the y-axis
So, traditionally, we add the arrow
So our answer is thus;
(x,y) right arrow (negative x , y)