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1 year ago

A grocery store has salmon fillets on sale for $8.30 per pound. Mrs.patrolia buys

1 answer:

4 0

not sure how much she bought, but all you’d have to do is multiply the cost of salmon fillets ($8.30) times the amount she bought.

Example: if Mrs. Patrolia bought 3 pounds it would be $8.30 x 3.

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A researcher is using a regular, two-tailed test with α = .05 to determine whether a non-zero correlation exists in the populati

beks73 [17]

Answer:

Step-by-step explanation:

Download docx

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3 years ago

B) If fencing costs $2.50/yd, determine the<br> costs of building the fence.

siniylev [52]

You didn’t give the rest of the answer hun

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2 years ago

Five cats each ate 1/4 cup of canned food . How much food did they eat altogether?

Sauron [17]

We have FIVE cats that each ate 1/4 cup of canned food.

Then, the five of them together ate:

5 times 1/4 cup This in mathematical expression is a profduct of an integer value (5) times the fraction (1/4) which we know how to multiply based on the problems we solved a few minutes ago:

5 * 1/4 = 5/1 * 1/4 = (5 * 1) / (1 * 4) = 5/4 cups

This answer can also be written as a MIXED number given that 5/4 is an IMPROPER fraction (a fraction with numerator larger than the denominator)

5/4 = 1 1/4

Not sure what answer your teacher would prefer. It depends on whether he/she wants you to use fractions or mixed numbers.

4 0

1 year ago

Money Flow The rate of a continuous money flow starts at $1000 and increases exponentially at 5% per year for 4 years. Find the

77julia77 [94]

Answer:

Present value = $4,122.4

Accumulated amount = $4,742

Step-by-step explanation:

Data provided in the question:

Amount at the Start of money flow = $1,000

Increase in amount is exponentially at the rate of 5% per year

Time = 4 years

Interest rate = 3.5% compounded continuously

Now,

Accumulated Value of the money flow = $1000e^{0.05t}$

The present value of the money flow = $\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t})} \, dt$

= $1000\int\limits^4_0 {e^{0.015t}} \, dt$

= $1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4$

= $1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]$

= 1000 × [70.7891 - 66.6667]

= $4,122.4

Accumulated interest = $e^{rt}\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t}} \, dt$

= $e^{0.035\times4}\times4,122.4$

= $4,742

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3 years ago

Decide if the converse is true for the following true conditional statement: "If I am in my kitchen, then I am at home." If it i

il63 [147K]

I am in my kitchen if and only if i am at home

not 100% right

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3 years ago

Read 2 more answers