Question

How much work is needed to stretch this spring a distance of 5.0 cm , starting with it unstretched?

Answer 1

The spring's work output while it is not extended is 5 J.

What is The Hooke's law ?

According to Hooke's law, as long as the elastic limit is not exceeded, the extension of a particular material is directly proportional to the force applied. Hence, we must be aware of that F = Ke

F = Applied force

Force constant is K.

Extension = e

F = applied force

Force constant is K.

Extension = e

Using the graph

K = F/e

F = 200N

E equals 5 cm or 5 * 10-2 m

K = 200N/ 5 * 10^-2 m

K = 4000 N/m

Now;

Work = 1/2Ke^2

Work = 0.5 * 4000 N/m * (5 * 10^-2 m)^2

Work = 5 J

To know  more about Hooke's Law visit:

brainly.com/question/13348278

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