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Vesnalui [34]
3 years ago
5

What expression is equivalent to -3(4x - 2) - 2x

Mathematics
1 answer:
bearhunter [10]3 years ago
4 0

Answer:

<em>-14x+6</em>

Step-by-step explanation:

first, we distribute the -3.

-3(4x - 2) - 2x=-12x+6-2x

than, we conbide like terms

-12x+6-2x=-14x+6

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He mathematics department of a college has 6 male​ professors, 8 female​ professors, 14 male teaching​ assistants, and 7 female
irinina [24]
Total number of people in the department = 6 + 8 + 14 + 7 = 35
Total males = 6 + 14 = 20
Total female professor = 8
Total males or professor = 20 + 8 = 28

P(\text {male or professor}) =  \dfrac{28}{35} =  \dfrac{4}{5}

\boxed {\boxed {\text {Answer: P(male or professor) = }\dfrac{4}{5} }}
3 0
3 years ago
Find the slope of the line that passes through (6, 7) and (2, 10). and simplify if needed thx guys.
tekilochka [14]

Answer:

-\frac{3}{4}

Step-by-step explanation:

the equation for finding the slope of a line when given two points is \frac{y_2-y_1}{x_2-x_1}, aka the change in y over the change in x.

pick one of your coordinate pairs to be y_2\\ and x_2. it doesn't matter which coordinate pair you choose as long as you keep them as y_2\\ and x_2. the remaining coordinate pair will be y_1 and x_1.

for this example, i'll use (2, 10) for y_2\\ and x_2 and (6, 7) for y_1 and x_1.

<em>**before i begin, i just want to note that you can do these next four steps in any order that you want. i personally prefer to plug in my y-values first and then my x-values, but you can choose to instead plug in the values of each coordinate pair (like starting by plugging in the coordinate pair (2, 10) with 10 for </em>y_2\\ and 2 for x_2<em>). it's up to you. i'm going to explain the steps by plugging in my y-values first and then my x-values because that's the way i normally do it.</em>

<em />

first, start by plugging in the y-value from the coordinate pair of your choosing in for y_2\\. since i chose (2, 10) for y_2\\ and x_2, i'll plug in 10 for y_2\\.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-y_1}{x_2-x_1}

then plug in the remaining coordinate pair's y-value in for y_1. since the coordinate pair that's left is (6, 7), i will plug in 7 for y_1.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-7}{x_2-x_1}

now i'm going to plug in the x-values. i chose (2, 10) to plug in for y_2\\ and x_2, so now i'll plug in 2 for x_2.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-7}{2-x_1}

and all that's left to plug in is the x-value from (6, 7), so i will plug that in for x_1.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-7}{2-6}

after plugging in all the values, you have \frac{10-7}{2-6}.

subtract 10 - 7 as well as 2 - 6.

\frac{10-7}{2-6} ⇒ \frac{3}{-4}

\frac{3}{-4} cannot be simplified, therefore the slope of the line is \frac{3}{-4} or -\frac{3}{4}.

i hope this helps! have a lovely day <3

7 0
3 years ago
A cone is inscribed in a right square pyramid. What is the remaining volume if the
diamong [38]

Answer:

3tgfjhihvyuvyuhihhibib

4 0
3 years ago
Help me please!!!!!!!!!!!!!!!!!!
Stella [2.4K]

Answer:

16/81

Step-by-step explanation:

(2/3)^4  = (2/3)*(2/3)*(2/3)*(2/3)

             = 16/81

4 0
3 years ago
An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p
horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

y=a(x+1)(x-5)=0

This gives

x=-1

y=5

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}

Thus the coordinates of B are:

B=(-1+\frac{2\sqrt{3} }{3},2)

Now this point B lies on the parabola, and therefore it must satisfy the equation  y=a(x+1)(x-5).

Thus

2=a((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)

Therefore

a=\frac{2}{((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)}

\boxed{a=-0.3575}

8 0
3 years ago
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