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Fofino [41]
1 year ago
9

Measurements have shown that the concentration of salt in seawater is 35.5 g-L. Calculate the volume in liters of seawater that

must be evaporated to recover 0.400 kg of salt. Be sure your answer has the correct number of significant digits
Chemistry
1 answer:
USPshnik [31]1 year ago
6 0

Answer:

Measurements have shown that the concentration of salt in seawater is 35.5 g-L. Calculate the volume in liters of seawater that must be evaporated to recover 0.400 kg of salt. Be sure your answer has the correct number of significant digits

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Draw the product formed by the reaction of potassium t-butoxide with (1s,2s)-1-bromo-2-methyl-1-phenylbutane (shown below). (dra
VikaD [51]
 <span>You have to use a Newman projection to make sure that the H on C#2 is anti-coplanar with the Br on C#1. (Those are the two things that are going to be eliminated to make the alkene.) 

My Newman projection looks like this when it's in the right configuration: 
Front carbon (C#2) has ethyl group straight up, H down/left, and CH3 down/right 
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Use this picture to explain that an electrically charged object can attract an uncharged object without any contact. Your answer
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Explanation:

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3 years ago
Phosphorite is a mineral that contains plus other non-phosphorus-containing compounds. What is the maximum amount of that can be
8_murik_8 [283]

Phosphorus can be prepared from calcium phosphate by the following reaction:

2Ca_3(PO_4)_2(s)+6SiO_2(s)+10C(s)\rightarrow 6CaSiO_3(s)+P_4(s)+ 10CO(g)

Phosphorite is a mineral that contains Ca_3(PO_4)_2 plus other non-phosphorus-containing compounds. What is the maximum amount of P_4 that can be produced from 2.3 kg of phosphorite if the phorphorite sample is 75% Ca_3(PO_4)_2 by mass? Assume an excess of the other reactants.

Answer: Thus the maximum amount of P_4 that can be produced is 0.345 kg

Explanation:

Given mass of phosphorite Ca_3(PO_4)_2  = 2.3 kg

As given percentage of phosphorite Ca_3(PO_4)_2 is = \frac{75}{100}\times 2.3kg=1.725kg=1725g

moles=\frac{\text {given mass}}{\text {Molar mass}}

{\text {moles of}Ca_3(PO_4)_2=\frac{1725g}{310g/mol}=5.56moles

2Ca_3(PO_4)_2(s)+6SiO_2(s)+10C(s)\rightarrow 6CaSiO_3(s)+P_4(s)+ 10CO(g)

According to stoichiometry:

2 moles of phosphorite gives = 1 mole of P_4

Thus 5.56 moles of phosphorite give= \frac{1}{2}\times 5.56=2.78moles of P_4

Mass of P_4=moles\times {\text {Molar mass}}=2.78mol\times 124g/mol=345g=0.345kg

Thus the maximum amount of P_4 that can be produced is 0.345 kg

5 0
3 years ago
Can alkenes react with potassium dichromate?
Lady bird [3.3K]
<span>alkenes donot react with potassium dichromate , but can react with potassium permanganate</span>
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