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algol13
4 years ago
11

Please answer 15 POINTS !!!

Chemistry
1 answer:
insens350 [35]4 years ago
6 0

Answer:

6 C O 2 + 6 H 2 O + Δ → C 6 H 12 O 6 + 6 O 2

Explanation:

The  Δ  symbol denotes added energy, here in the form of sunlight. Strong  C = O , and  O − H  bonds have been broken, and this bond cleavage is only partially energetically compensated by the formation of  C − H  and  O = O  bonds. Hence the reaction is endothermic (energy input on LHS). Note that the reaction is balanced with respect to mass and charge (says he, checking to see whether it is indeed balanced!).

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What is group 3-12 on the piratic table
katen-ka-za [31]
If you mean periodic table, then it's metals
4 0
3 years ago
Consider the following reaction at equilibrium: 2NH3 (g) N2 (g) + 3H2 (g) Le Châtelier's principle predicts that the moles of H2
Lilit [14]

Answer:

A decrease in the total volume of the reaction vessel (T constant)

Explanation:

  • Le Châtelier's principle predicts that the moles of H2 in the reaction container will increase with a decrease in the total volume of the reaction vessel.
  • <em><u>According to the Le Chatelier's principle, when a chnage is a applied to a system at equilibrium, then the equilibrium will shift in a way that counteracts the effect causing it.</u></em>
  • In this case, a decrease in volume means there is an increase in pressure, therefore the equilibrium will shift towards the side with the fewer number of moles of gas.
3 0
4 years ago
Ammonia is formed according to the reaction below. A chemist mixes 21 grams of nitrogen gas and 18 grams of hydrogen gas in a 2.
Rama09 [41]

Answer : The mass of hydrogen gas consumed will be, 4.5 grams

Explanation : Given,

Mass of N_2 = 21 g

Mass of H_2 = 18 g

Molar mass of N_2 = 28 g/mole

Molar mass of H_2 = 2 g/mole

First we have to calculate the moles of N_2 and H_2.

\text{Moles of }N_2=\frac{\text{Mass of }N_2}{\text{Molar mass of }N_2}=\frac{21g}{28g/mole}=0.75moles

\text{Moles of }H_2=\frac{\text{Mass of }H_2}{\text{Molar mass of }H_2}=\frac{18g}{2g/mole}=9moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

From the given balanced reaction, we conclude that

As, 1 mole of N_2 react with 3 moles of H_2

So, 0.75 moles of N_2 react with 3\times 0.75=2.25 moles of H_2

From this we conclude that, H_2 is an excess reagent because the given moles are greater than the required moles and N_2 is a limiting reagent because it limits the formation of product.

The moles of hydrogen gas consumed = 2.25 mole

Now we have to calculate the mass of hydrogen gas consumed.

\text{Mass of }H_2=\text{Moles of }H_2\times \text{Molar mass of }H_2

\text{Mass of }H_2=(2.25mole)\times (2g/mole)=4.5g

Therefore, the mass of hydrogen gas consumed will be, 4.5 grams

5 0
4 years ago
Type of reaction based on the reactants<br> FeCl3 +K →
strojnjashka [21]

Answer:

complexation

Explanation:

KSCN + FeCl 3 → K + + [FeSCN] 2+ + 3 Cl. This is a complexation reaction: [FeSCN] 2+ is the formed complex.

3 0
3 years ago
Every morning, Sarah prepares the same amount of coffee at the same temperature. Identify the coffee solution with the highest c
saw5 [17]

So if you are trying to find the coffee with the highest concentration of sugar, the cup that has the highest concentration of sugar is the cup that Sarah made on Thursday.

Since there were sugar molecules remaining at the bottom of her coffee cup, that means that the coffee solution was completely saturated with sugar - no more sugar was able to dissolve in the coffee.

6 0
4 years ago
Read 2 more answers
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