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masya89 [10]
3 years ago
5

An element has two isotopes, A and B, with mass numbers of 32.0 and 33.0 respectively. The relative atomic mass is 32.3. The per

centage abundance of the two isotopes is:
a) A - 20% B - 80%

b) A - 25% B - 75%

c) A - 80% B - 20%

d) A - 70% B - 30%

e) A - 50% B - 50%
Chemistry
2 answers:
vlada-n [284]3 years ago
7 0

Answer:

d) A - 70% B - 30%

Explanation:

If x is the abundance of A, and 1−x is the abundance of B, then:

x (32.0) + (1−x) (33.0) = 32.3

32x + 33 − 33x = 32.3

33 − x = 32.3

x = 0.7

The abundance of A is 70%, and the abundance of B is 30%.

Stolb23 [73]3 years ago
7 0

D is the correct answer

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3 years ago
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A buffer with a pH of 4.31 contains 0.31 M of sodium benzoate and 0.24 M of benzoic acid. What is the concentration of [ H 3 O ]
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<u>Explanation:</u>

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Putting values in above equation, we get:

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<u>Initial:</u>           0.24          0.060              0.31

<u>Final:</u>             0.18          -                     0.37

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pH=pK_a+\log(\frac{[\text{conjugate acid}]}{[\text{base}]})

pH=pK_a+\log(\frac{[C_6H_5COO^-]}{[C_6H_5COOH]})

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pH=-\log[H_3O^+]

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Putting values in above equation, we get:

3.89=-\log[H_3O^+]

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3 0
3 years ago
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