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MAVERICK [17]
2 years ago
11

a 5.0 kg block is at rest on a horizontal floor. if you push horizontally on the 5.0 kg block with a force of 15.0 n, it just st

arts to move, find the coefficient of static friction?
Physics
1 answer:
zheka24 [161]2 years ago
4 0

For the 5.0Kg block with the force of 15 Newton, the coefficient of static friction (μ) comes out to be 0.306. Applying the formula F = μmg.

Static friction acts on stationary body/body at rest. Let μ be the coefficient of static friction between the block and the horizontal floor.

Using the formula: F = μmg

Where,

F = Force , m= mass of the block and g = gravity.

and values of: m= 5.0Kg, F= 15.0N, g= 9.8m/s²

We can get: μ = F/(mg)

μ = 15/49

μ =0.306

Therefore, coefficient of static friction (μ) = 0.306.

To learn more about static friction visit the link- brainly.com/question/13680415

#SPJ4

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<h3>Definition of pH</h3>

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:

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<h3>Definition of pOH</h3>

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<h3>Concentration of H⁺ ions</h3>

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<u><em>[H⁺]= 10⁻⁸= 1×10⁻⁸ M</em></u>

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<h3>Concentration of OH⁻ ions</h3>

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Replacing in the definition of pOH the concentration of OH⁻ ions is obtained:

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Solving

<u><em>[OH⁻]= 10⁻⁶= 1×10⁻⁶ M</em></u>

Finally, the concentration of OH⁻ ions at pH=8 is 1×10⁻⁶ M.

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brainly.com/question/16032912

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