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Makovka662 [10]
3 years ago
9

The element in a fluorescent lightbulb that absorbs UV light and releases visible light energy is ____?

Physics
2 answers:
Agata [3.3K]3 years ago
8 0
You're answer will be a phosphor 
The element in a florescent lightbulb that absorbs UV light and releases visible light energy is --a phosphor--. 
Mnenie [13.5K]3 years ago
3 0
So in a fluorescent light bulb the mercury atoms release the UV light. This UV light is absorbed by the phosphorous powder coating inside and this releases the visible light.
So your answer is phosphorous powder.
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COMPLETE QUESTION:

<em>When the magnetic flux through a single loop of wire increases by </em>30 Tm^2<em> , an average current of 40 A is induced in the wire. Assuming that the wire has a resistance of </em><em>2.5 ohms </em><em>, (a) over what period of time did the flux increase? (b) If the current had been only 20 A, how long would the flux increase have taken?</em>

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(b).

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\Delta t = \dfrac{30Tm^2}{(20A)(2.5\Omega)},

\boxed{\Delta t = 0.6 s\\}

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