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MaRussiya [10]
3 years ago
10

Derek designed an experiment to demonstrate interactions between Earth systems. He cleared a patch of land in his backyard and p

oured a glass of water from a height of 12 inches above the ground. A depression was formed on the land at the spot where the water hit the ground. What does Derek's experiment best demonstrate?
Physics
1 answer:
vesna_86 [32]3 years ago
6 0

Derek's experiment best demonstrates the effects of gravity, that force made the water go down and  hit the ground, the effect of that was a depression.

The definition of Hydrosphere is all the water of earth surface, so the water represents Hydrosphere.

The definition of Geosphere is the surface of Earth, when the water fell down and touched the ground it caused an interaction between Hydrosphere and Geosphere.

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What might happen if a person’s ear canal was blocked?
mylen [45]

Answer:

D. Sounds would be harder to hear.

Explanation:

if the ear canal is blocked then the sound waves cannot reach the ear drum thus we cannot hear clearly.

hope this helps please mark as brainliest:)

7 0
3 years ago
A 40kg dog is sitting on top of a hillside and has a potential energy of 1,568 J. What is the height of the hill side?
bagirrra123 [75]

Answer:

<h2>39.2 m</h2>

Explanation:

The height of the hill side can be found by using the formula

h =  \frac{p}{m}  \\

p is the potential energy

m is the mass

From the question we have

h =  \frac{1568}{40}  =  \frac{196}{5}  \\

We have the final answer as

<h3>39.2 m</h3>

Hope this helps you

5 0
3 years ago
Read 2 more answers
William WangHomework #33 Regents Review (3)0989Assignment Mode : Open (Time On Task) 9 of 25 ListenDuring a collision, an 84-kil
Lemur [1.5K]

Answer:

1.7\cdot 10^3 N

Explanation:

The impulse theorem states that the product between the force and the time interval of the collision is equal to the change in momentum:

F \Delta t = m \Delta v

where

F is the force

\Delta t is the time interval

m is the mass

\Delta v is the change in velocity

Here we have

m = 84 kg

\Delta t = 1.2 s

\Delta v = 24 m/s

So we can solve the equation to find the force:

F= \frac{m \Delta v}{\Delta t }=\frac{(84 kg)(24 m/s)}{1.2 s}=1680 N \sim 1.7\cdot 10^3 N

4 0
3 years ago
Two mass m1 and m2 lie on a frictionless surface. Between the two masses is a compressed spring, with spring constant k. The sys
max2010maxim [7]

Answer:

The spring was compressed the following amount:

\Delta x=\sqrt{ \frac{m_1\,v_1^2+ m_2\,v_2^2}{k} }

Explanation:

Use conservation of energy between initial and final state, considering that the surface id frictionless, and there is no loss in thermal energy due to friction. the total initial energy is the potential energy of the compressed spring (by an amount \Delta x), and the total final energy is the addition of the kinetic energies of both masses:

E_i=\frac{1}{2} k\,(\Delta x)^2\\\\E_f=\frac{1}{2} m_1\,v_1^2+\frac{1}{2} m_2\,v_2^2

E_i=E_f\\

\frac{1}{2} k\,(\Delta x)^2=\frac{1}{2} m_1\,v_1^2+\frac{1}{2} m_2\,v_2^2\\k\,(\Delta x)^2=m_1\,v_1^2+ m_2\,v_2^2\\(\Delta x)^2=\frac{m_1\,v_1^2+ m_2\,v_2^2}{k} \\\Delta x=\sqrt{ \frac{m_1\,v_1^2+ m_2\,v_2^2}{k} }

8 0
3 years ago
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