Energy = Planck's constant * Frequency
E = (6.62607004 × 10⁻³⁴<span>) * 7 * 10</span>¹⁴
E = 46.38 * 10⁻²⁰
E = 4.638 * 10⁻¹⁹ J
Hope this helps!
your answer will be :
B. <u>Na has a lower</u> <u>electronegativity than H</u>
because Na belongs to alkali metals which are least electronegative (most electro positive) but hydrogen is a non metal, it has higher electronegativity as compared to metals like Sodium (Na).
Yes u can do it but using all of ur answer