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3 years ago

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What do all prokaryotes and eukaryotes have in common? A. They are unicellular organisms. B. They are multicellular organisms. C

. The cells that make them up each contain genetic information. D. The cells that make them up each contain a membrane-enclosed nucleus.

1 answer:

vodomira [7]3 years ago

4 0

They are multicellular

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Explanation:

This would be similar to how the poles work in the North and South. Due to their placement, they recieve much more sun light than the rest of the Earth since we rotate horizontally. However, their placement also makes them farther from the sun than the rest of Earth, therefore not receiving as much heat.

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Describe the orbital diagram of an atom with six electrons. Explain how this orbital diagram demonstrates Hund's rule.

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Answer:

See explanation

Explanation:

According to Hund's rule, electrons must occur singly first before pairing takes place.

If I want to fill six electrons into orbitals, the filling of electrons will be as follows;

1s2 2s2 2p2.

The first four electrons are filled into the 1s and 2s levels having only one orbital each. The fifth and sixth electrons are filled into 2p orbitals. The 2p level have three degenerate orbitals. The two electrons are singly filled into each of the degenerate orbitals in accordance to Hund's rule.

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Which of these is MOST LIKELY to contribute to the long-term instability of a local ecosystem? A) storms that uproot large trees

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There are multiple cases in recorded history where invasive species have ruined ecosystems and even driven some species to extinction. An example of this is the dodo bird which went extinct due partially due to the invasion of rats into their habitats.

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3 years ago

Read 2 more answers

3. During an experiment where 50.0 mL of a 1.0 M acid solution was mixed with 50.0 mL of a 1.0 M base solution, the temperature

Aleksandr-060686 [28]

Answer:

$\large \boxed{\text{-61 kJ$\cdot$mol$^{-1}$}}$

Explanation:

Data:

H₃O⁺ + OH⁻ ⟶ 2H₂O

V/mL: 50.0 50.0

c/mol·L⁻¹: 1.0 1.0

ΔT = 6.5 °C

ρ = 1.210 g/mL

C = 4.18 J·°C⁻¹g⁻¹

C_cal = 12.0 J·°C⁻¹

Calculations:

(a) Moles of acid

$\text{Moles of acid} = \text{0.0500 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{0.0500 mol}\\\\\text{Moles of base} = \text{0.0500 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{0.0500 mol}$

(b) Volume of solution

V = 50.0 mL + 50.0 mL = 100.0 mL

(c) Mass of solution

$\text{Mass of solution} = \text{100.0 mL} \times \dfrac{\text{1.10 g}}{\text{1 mL}} = \text{110.0 g}$

(d) Calorimetry

There are three energy flows in this reaction.

q₁ = heat from reaction

q₂ = heat to warm the water

q₃ = heat to warm the calorimeter

q₁ + q₂ + q₃ = 0

nΔH + mCΔT + C_calΔT = 0

0.0500ΔH + 1.10×4.18×6.5 + 12.0×6.5 = 0

0.0500ΔH + 2989 + 78.0 = 0

0.0500ΔH + 3067 = 0

0.0500ΔH = -3067

ΔH = -3067/0.0500

= -61 000 J/mol

= -61 kJ/mol

$\text{The enthalpy of reaction is $\large \boxed{\textbf{-61 kJ$\cdot$mol$^{\mathbf{-1}}$}}$}$

Note: The answer can have only two significant figures because that is all you gave for the change in temperature.

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$H_2O+CO_2\leftrightharpoons H_2CO_3$

This compound formed by this reaction is acid, carbonic acid.

Them the pH will get lower them normal, and our buld send an action to our body, and this reaction will be the <span>breathing.</span>

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