Five hundred twenty million, three hundred and forty thousand. hope it helps!
Answer:
Explanation:
We shall find out volume of air at NTP or at 273 K and 10⁵ Pa ( 1 atm )
Let it be V₂
V₂ = 7.87 litres
22.4 litres of any gas is equivalent to 1 mole
7.87 litres of air will be equivalent to
7.87 / 22.4 moles
= .35 moles .
Answer:
It would react better than what with dilute and will furnish more hydrogen gas.
Answer:
266.7 g
Explanation:
Molar mass of AlCl3=133.3405 g
2AlCl3=2×133.34
=266.7 g
Please mark brainliest
Answer:
157.29 Torr
Explanation:
This question may be solved by the mole fraction.
Mole fraction → Moles of gas / Total moles = Partial pressure of gas / Total pressure
If the atmosphere is about 21% you assume that the mole fraction is 0.21 so:
0.21 = Partial pressure of gas / Total pressure
0.21 = Partial pressure of gas / 749 Torr
Partial pressure of the gas = 749 Torr . 0.21 → 157.29 Torr
