Question

A certain shade of blue has a frequency of 7.00 × 1014 Hz. What is the energy of exactly one photon of this light?

Answer 1

Energy = Planck's constant * Frequency 

E = (6.62607004 × 10⁻³⁴) * 7 * 10¹⁴

E = 46.38 * 10⁻²⁰

E = 4.638 * 10⁻¹⁹ J

Hope this helps!

Answer 2

Answer : The energy of exactly one photon of this light is $4.64\times 10^{-19}J$

Explanation : Given,

Frequency of blue light = $7.00\times 10^{14}Hz=7.00\times 10^{14}s^{-1}$

Formula used :

$E=h\times \nu$

where,

$\nu$ = frequency of light

h = Planck's constant = $6.626\times 10^{-34}Js$

Now put all the given values in the above formula, we get:

$E=(6.626\times 10^{-34}Js)\times (7.00\times 10^{14}s^{-1})$

$E=4.64\times 10^{-19}J$

Therefore, the energy of exactly one photon of this light is $4.64\times 10^{-19}J$