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2 years ago

In this equation, which are the reactant(s) Mg(s)+o(g) =Mgo(s)

Chemistry

1 answer:

Mekhanik [1.2K]2 years ago

6 0

Hello,

In the left side, Mg and O are reactants... and MgO is the product....

Hope it helped you... pls mark brainliest

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1. The solubility of lead(II) chloride at some high temperature is 3.1 x 10-2 M. Find the Ksp of PbCl2 at this temperature.

solniwko [45]

Answer:

1) The solubility product of the lead(II) chloride is $1.2\times 10^{-4}$ .

2) The solubility of the aluminium hydroxide is $1.6\times 10^{-10} M$ .

3)The given statement is false.

Explanation:

Solubility of lead chloride = $S=3.1\times 10^-2M$

$PbCl_2(aq)\rightleftharpoons Pb^{2+}(aq)+2Cl^-(aq)$

S 2S

The solubility product of the lead(II) chloride = $K_{sp}$

$K_{sp}=[Pb^{2+}][Cl^-]^2$

$K_{sp}=S\times (2S)^2=4S^3=4\times (3.1\times 10^{-2})^3=1.2\times 10^{-4}$

The solubility product of the lead(II) chloride is $1.2\times 10^{-4}$ .

Concentration of aluminium nitrate = 0.000010 M

Concentration of aluminum ion = $1\timed 0.000010 M=0.000010 M$

Solubility of aluminium hydroxide in aluminum nitrate solution = $S$

$Al(OH)_3(aq)\rightleftharpoons Al^{3+}(aq)+3OH^-(aq)$

S 3S

The solubility product of the aluminium nitrate = $K_{sp}=1.0\times 10^{-33}$

$K_{sp}=[Al^{3+}][OH^-]^3$

$1.0\times 10^{-33}=(0.000010+S)\times (3S)^3$

$S=1.6\times 10^{-10} M$

The solubility of the aluminium hydroxide is $1.6\times 10^{-10} M$ .

$Molarity=\frac{Moles}{Volume (L)}$

Mass of NaCl= 3.5 mg = 0.0035 g

1 mg = 0.001 g

Moles of NaCl = $\frac{0.0035 g}{58.5 g/mol}=6.0\times 10^{-5} mol$

Volume of the solution = 0.250 L

$[NaCl]=\frac{6.0\times 10^{-5} mol}{0.250 L}=0.00024 M$

1 mole of NaCl gives 1 mole of sodium ion and 1 mole of chloride ions.

$[Cl^-]=[NaCl]=0.00024 M$

Moles of lead (II) nitrate = n

Volume of the solution = 0.250 L

Molarity lead(II) nitrate = 0.12 M

$n=0.12 M]\times 0.250 L=0.030 mol$

1 mole of lead nitrate gives 1 mole of lead (II) ion and 2 moles of nitrate ions.

$[Pb^{2+}]=[Pb(NO_2)_3]=0.030 M$

$PbCl_2(aq)\rightleftharpoons Pb^{2+}(aq)+2Cl^-(aq)$

Solubility of lead(II) chloride = $K_{sp}=1.2\times 10^{-4}$

Ionic product of the lead chloride in solution :

$Q_i=[Pb^{2+}][Cl^-]^2=0.030 M\times (0.00024 M)^2=1.7\times 10^{-9}$

$Q_i$ ( no precipitation)

The given statement is false.

3 0

3 years ago

Read the false statement.

liq [111]

Answer:

The second one is the correct statement.

Explanation:

An atom consists of a dense, heavy, positively charged central part called nucleus. It consists of neutrons and protons.

The electrons revolves around the nucleus in circular paths. These electrons are called planetary electrons because they can be compared to various planets revolving around the sun and the nucleus is compared with sun.

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2 years ago

Answer the following questions:

Vera_Pavlovna [14]

Answer:

fdfdgiukjgrguhjnfvthhhdqddwsvhjjj

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2 years ago

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Vera_Pavlovna [14]

Answer:

Energy is transferred from one object to another when a reaction takes place.

Explanation:

Energy comes in many forms and can be transferred from one object to another as heat, light, or motion, to name a few.

The answer could be It is a well known fact that energy can neither be created and nor be destroyed but can be transformed from one form to another.

Now talking about your example in a typical light bulb electrical energy is converted into light energy and heat energy. Now when the electric current flows through the conductor/filament in the light bulb,this would cause vibrations and the free ions are more likely to go to an higher energy level,and when the ions come back to their original state,the difference in the two energy levels is usually emitted as a photon,thus light energy is obtained and the heat energy is the energy dissipated as a result of flow of electricity through the conductor.

Anything that gets transformed into light energy or in better words ElectroMagnetic Energy would be a result of this.

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3 years ago

Element with the largest electron cloud

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