1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dexar [7]
3 years ago
6

A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V?What is the total energy stores in the

electic field?U=______ JWhat is the energy densityu=________J/m^3
Physics
1 answer:
Rama09 [41]3 years ago
7 0

1) 1.11\cdot 10^{-7} J

The capacitance of a parallel-plate capacitor is given by:

C=\frac{\epsilon_0 A}{d}

where

\epsilon_0 is the vacuum permittivity

A is the area of each plate

d is the distance between the plates

Here, the radius of each plate is

r=\frac{2.0 cm}{2}=1.0 cm=0.01 m

so the area is

A=\pi r^2 = \pi (0.01 m)^2=3.14\cdot 10^{-4} m^2

While the separation between the plates is

d=0.50 mm=5\cdot 10^{-4} m

So the capacitance is

C=\frac{(8.85\cdot 10^{-12} F/m)(3.14\cdot 10^{-4} m^2)}{5\cdot 10^{-4} m}=5.56\cdot 10^{-12} F

And now we can find the energy stored,which is given by:

U=\frac{1}{2}CV^2=\frac{1}{2}(5.56\cdot 10^{-12} F/m)(200 V)^2=1.11\cdot 10^{-7} J

2) 0.71 J/m^3

The magnitude of the electric field is given by

E=\frac{V}{d}=\frac{200 V}{5\cdot 10^{-4} m}=4\cdot 10^5 V/m

and the energy density of the electric field is given by

u=\frac{1}{2}\epsilon_0 E^2

and using

E=4\cdot 10^5 V/m, we find

u=\frac{1}{2}(8.85\cdot 10^{-12} F/m)(4\cdot 10^5 V/m)^2=0.71 J/m^3

You might be interested in
Question 3 Please, i need help! Thank you
Tom [10]
I don't know this 1 I'm sorry I can't help you 
4 0
3 years ago
In a city grid, each block on the east-west streets is 100 meters long. Each block on the north-south streets is 20 meters long.
alex41 [277]

Answer:

72.1 m

Explanation:

Hello!

When the walker walks west, each block he walks will be of 100 m, so the walker walked 4*100m = 400 m west.

Similarly, when the walker walks south, he walks 20 meters per block, therefore, the walker walked 4*20 m = 80 m south.

Since the directions west and south are perpendicular, the distance between the start ad end point is:

d = √(400^2 + 80^2) m = 407.92 m

However the walker traveled 480 m

Therefore, the walker traveled 480 - 407.9 m = 72.1 m farther than the actual distance

8 0
3 years ago
The difference between the observed points and the regression line points is equal to the:________
pshichka [43]

The difference between the observed points and the regression line points is equal to the correlation.

The strength and direction of a relationship between two or more variables are described by the statistical measure of correlation, which is given as a number. However, a correlation between two variables does not necessarily imply that a change in one variable is the reason for a change in the values of the other.

Regression expresses the relationship as an equation, whereas correlation assesses the strength of the linear link between two variables. The square of the correlation coefficient, also known as Pearson's r, between the observed and predicted values in a regression is sometimes referred to as R2.

Learn more about correlation here;

brainly.com/question/6563788

#SPJ4

8 0
2 years ago
What are discretionary calories?
AleksAgata [21]
<span>is the excess </span>calories<span> you can have once you get your required nutrient  </span><span>
those excess calories can come from higher forms of fat such as milk cheese and meat and sugary items such as syrup butter and any sauce those calories can also come from pop candy and alcohol </span>
8 0
3 years ago
What is the efficiency of an engine that puts out 250 J of work for every 500 J of heat put into it?
Oliga [24]

If you put 300 J of heat into an engine with an efficiency of 0.35, how much work can be done? 3. How much energy must be put into an engine with an efficiency of 0.6 if 270 J of work are required? 4. An engine with an efficiency of 0.425 uses 1200 J of energy. Find the amount of energy wasted by the engine. 5. Calculate the efficiency of an engine operating between temperatures of 258 K and 600 K 6. An engine runs with its exhaust (cold) reservoir at a temperature of 200 K. To what temperature should the input (hot) temperature be set if an efficiency of 0.8 is desired? 7. Complete the following table of temperatures. Fahrenheit Celsius Kelvin 213 15 98.6 75 408

5 0
2 years ago
Other questions:
  • It is more difficult to start moving a heavy carton from rest than it is to keep pushing it with a constant velocity because
    13·2 answers
  • Which best compares the gravitational force and the strong force ?
    14·2 answers
  • Which is larger, the Sun's pull on Earth or Earth's pull on the Sun?
    15·1 answer
  • If the earth can travel 1800 km in 1 minute what is it’s speed in km/s
    14·1 answer
  • 12)
    13·1 answer
  • A ______ is a push or pull that one object exerts on another.
    13·2 answers
  • Express in words AND mathematically the relationship between…<br> Period and frequency
    14·1 answer
  • What causes a objects to move or stay still? claim and evidence
    5·1 answer
  • A student's tonsils become infected and she has them removed. What condition does she need to be careful of in the future?
    15·1 answer
  • Why is nuclear energy able to be used for practical purposes? the reactions are controlled to regulate energy output. the reacti
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!