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Vladimir [108]
1 year ago
10

an experiment calls for you to use 100 mlml of 0.80 mm hno3hno3 solution. all you have available is a bottle of 4.2 mm hno3hno3

. how many milliliters of the 4.2 mm hno3hno3 solution do you need to prepare the desired solution? how many milliliters of water do you need to prepare the desired solution?
Chemistry
1 answer:
Sever21 [200]1 year ago
8 0

19.04 milliliters of water do you need to prepare the desired solution.

Formula, C1 × V1 = C2 × V2

C = Concentration

V = Volume

V1 = 100 ml

C1 = 0.80 M

C2 = 4.2 M

V2 = ?

Put these values in the formula, C1 × V1 = C2 × V2

V2 = (C1 × V1) / C2

     = (0.80 × 100) / 4.2

     = 19.04 ml

Therefore, 19.04 milliliters of water do you need to prepare the desired solution.

In chemistry, a homogenous combination of two or extra materials in relative quantities that may be various continuously up to what is known as the restrict of solubility. The term solution is typically carried out to the liquid country of be counted, however answers of gases and solids are possible.

So, based totally on the quantity of solute gift, answers are labeled into three sorts: unsaturated solutions and saturated answers. Unsaturated answer: an answer wherein greater amount of solute may be dissolved with out elevating its temperature, is referred to as an unsaturated solution.

Learn more about solution here:- brainly.com/question/25326161

#SPJ4

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Calculate the amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C.
qwelly [4]

Answer:

The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

Between heat and temperature there is a direct proportional relationship. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

  • c= 4.184 \frac{J}{g*C}
  • m= 32 g
  • ΔT= Tfinal - Tinitial= 22°C - 8°C= 14°C

Replacing:

Q= 32 g* 4.184 \frac{J}{g*C} *14 °C

Solving:

Q= 1,874.432 J

<u><em>The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J</em></u>

7 0
2 years ago
What is the volume (in dm3 of 1 mole of oxygen at 5 MPa and 200 K?
vodka [1.7K]

<u>Answer:</u> The volume of oxygen gas is 0.332dm^3

<u>Explanation:</u>

To calculate the volume of the gas, we use the equation given by ideal gas equation:

PV=nRT

where,

P = pressure of the gas = 5 MPa = 5000 kPa   (Conversion factor: 1 MPa = 1000 kPa)

V = Volume of gas = 3.34 L

n = number of moles of oxygen gas = 1 mole

R = Gas constant = 8.31dm^3\text{ kPa }mol^{-1}K^{-1}

T = Temperature of the gas = 200 K

Putting values in above equation, we get:

5000kPa\times V=1mol\times 8.31dm^3\text{ kPa }mol^{-1}K^{-1}\times 200K\\\\V=0.332dm^3

Hence, the volume of oxygen gas is 0.332dm^3

7 0
3 years ago
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