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Zarrin [17]
3 years ago
13

How many electron dots should As have?

Chemistry
1 answer:
Effectus [21]3 years ago
8 0

Answer:

5

Explanation:

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Given the reaction: 4 NH3(g) + 5 O2(g) → 4 NO (g) + 6 H2O When 1.20 mole of ammonia reacts, how many moles of water are produced
Ganezh [65]

Answer:

When 1.20 mole of ammonia reacts, 1.8 moles of water are produced.

Explanation:

The balanced reaction is:

4 NH₃(g) + 5 O₂(g) → 4 NO (g) + 6 H₂O

By stoichiometry of the reaction, the following amounts of moles participate in the reaction:

  • NH₃: 4 moles
  • O₂: 5 moles
  • NO: 4 moles
  • H₂O:  6 moles

Then you can apply the following rule of three: if by stoichiometry 4 moles of ammonia produce 6 moles of water, 1.2 moles of ammonia will produce how many moles of water?

moles of water=\frac{1.2 moles of ammonia*6 moles of water}{4 moles of ammonia}

moles of water= 1.8 moles

<u><em>When 1.20 mole of ammonia reacts, 1.8 moles of water are produced.</em></u>

<u><em></em></u>

8 0
2 years ago
What volume will 50.2 grams of co2 (g) occupy at stp?
Genrish500 [490]
Number of moles of CO2 =
Mass /Ar
= 50.2 / (12 + 32)
1.14 mols

For every 1 mol of gas, there will be
24000 cm^3 of gas

Vol. = 1.14 x 24 dm^3
= 27.36 dm^3
8 0
3 years ago
The law of definite proportions helps us explain why water will always        A. break down into gas when heated.   B. be releas
NikAS [45]
... liquid water are two different forms of the same chemical substance, water. A chemical substance is a form of matter that has constant chemical ...
8 0
2 years ago
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¿Cuántos lunares hay en 1,035 gramos plomo <br>​
SpyIntel [72]

Answer:

TERO BAU KO CHAK

...BUJHIS

8 0
3 years ago
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The enthalpy change for converting 1.00 mol of ice at -50.0°c to water at 70.0°c is __________ kj. the specific heats of ice, wa
kogti [31]
First, calculate for the amount of heat used up for increasing the temperature of ice.

      H = mcpdT
       H = (18 g)*(2.09 J/g-K)(50 K) = 1881 J

Then, solve for the heat needed to convert the phase of water.
    H = (1 mol)(6.01 kJ/mol) = 6.01 kJ = 6010 J

Then, solve for the heat needed to increase again the temperature of water.
    H = (18 g)(4.18 J/gK)(70 k)
    H = 5266.8 J

The total value is equal to 13157.8 J

Answer: 13157.8 J
8 0
3 years ago
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