Question

What is the volume (in dm3 of 1 mole of oxygen at 5 MPa and 200 K?

Answer 1

Answer: The volume of oxygen gas is $0.332dm^3$

Explanation:

To calculate the volume of the gas, we use the equation given by ideal gas equation:

$PV=nRT$

where,

P = pressure of the gas = 5 MPa = 5000 kPa   (Conversion factor: 1 MPa = 1000 kPa)

V = Volume of gas = 3.34 L

n = number of moles of oxygen gas = 1 mole

R = Gas constant = $8.31dm^3\text{ kPa }mol^{-1}K^{-1}$

T = Temperature of the gas = 200 K

Putting values in above equation, we get:

$5000kPa\times V=1mol\times 8.31dm^3\text{ kPa }mol^{-1}K^{-1}\times 200K\\\\V=0.332dm^3$

Hence, the volume of oxygen gas is $0.332dm^3$