The first thing that the nurse should do is TO START CHEST COMPRESSION.
Cardiopulmonary arrest refers to a sudden loss of blood flow, which occur as a result of the failure of the heart to actively pump blood. Performing chest compress on a victim of cardiopulmonary attack will help to restore the pumping function of the heart again.
1. The lining up of chromosomes by the spindle fibers takes place at metaphase II phase. It is the second stage of meiosis II, the spindle draws the chromosomes towards the metaphase plate.
2. The formation of the nuclear envelope around each set of DNA takes place in telophase II. Along with the formation of the nuclear envelope, the process of cytokinesis also takes place in telophase II, producing four daughter cells, each comprising a haploid set of chromosomes.
3. The sister chromatids are pulled apart in anaphase II stage. In this phase, the sister chromatids are migrated towards the opposite poles of the cell with the help of protein fibers.
4. The centromeres are moved towards the poles of the cell at prophase II stage.
The best answer is D.
A carbon sink is anything that absorbs more carbon than it produces or releases.
The main carbon sinks found in nature are plants, the ocean and soil. Plants such as trees capture carbon dioxide from the atmosphere and use it in photosynthesis. Part of this carbon is transferred to soil as the trees and other plants die and decompose.
Due to the effectiveness of trees and other plants as carbon sinks, the Kyoto protocol proposed that emission reduction can be achieved through absorption of carbon dioxide by these plants.
Answer:
Zero (0)
Explanation:
According to the given information the genotype of the woman with blood type "AB" would by I^AI^B. The genotype of the man with blood type O would be "ii". Here, the alleles I^A and I^B are dominant over the allele "i".
A cross between parents with genotype I^AI^B and ii would give 50% of children with I^Ai genotype and 50% of children with I^Bi genotype. The children with "I^Ai genotype" would have blood type "A" and the children with I^Bi genotype would have blood type "B". This couple is never likely to have any child with blood type "O" since the mother does not carry allele "i".
Cross: I^AI^B x ii = 1/2 I^Ai : 1/2 I^Bi