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SSSSS [86.1K]
2 years ago
12

Describing trends in scatter plots1The graph below shows the relationship between life expectancyand infant mortality rate in a

random sample of countries,Which statement is the best description of the associationbetween these variables?Choose 1 answerCountries with higher infant mortality rates tended to have longerlife expectanciesCountries with higher infant mortality rates tended to haveshorter life expectancies.There is no clear relationship between infant mortality rates andlife expectancyWhich statement is the best description of the association between these variables

Mathematics
1 answer:
rosijanka [135]2 years ago
5 0
Given

The graph of the infant mortality rate and life expectancy is given in the scatter form.

Explanation

To determine the relation between the life expectancy and infant mortality rate ,

use the given graph.

From the graph given, it is clear that as the infant mortality rate increases then the life expectancy decreases.

Therefore, the countries with high mortality rates tended to have shorter life expectancies.

Answer

Hence the correct option is B.

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You need to put your reindeer, Gloopin, Quentin, Ezekiel, and Lancer, in a single-file line to pull your sleigh. However, Quenti
LekaFEV [45]

Answer:

Not 100% sure but the most I got was 12 ways

Hope this helps :)

4 0
4 years ago
To the nearest hundredth, what is the value of x?<br><br> 42.15<br> 43.11<br> 52.07<br> 54.26
Gnesinka [82]

Answer:

52.07

Step-by-step explanation:

sin of an angle is the opposite side over the hypotenuse

sin 51 = x/67

Multiply each side by 67

67 sin 51 = x

52.06877942 =x

Rounding to the nearest hundredth

52.07 =x

3 0
3 years ago
Park officials make predictions of times to the next eruption of a particular​ geyser, and collect data for the errors​ (minutes
nalin [4]

Answer:

a) Null hypothesis: \mu =0

Alternative hypothesis: \mu \neq 0

b) t =-7.44

c) p_v = 2*P(t_{98}

d) Reject Null hypothesis. The is enough evidence to conclude that the mean prediction error is not equal to 0.

We reject the null hypothesis because the p_v. So we can conclude that the difference is significantly different from 0 at 5% of significance.

Step-by-step explanation:

Assuming this output:

t_{difference}=-0.395

t(observed value) =-7.44

t(Critical value )= 1.984

DF = 98

p value (two tailed) < 0.0001

\alpha =0.05

a) What are the null and alternative hypothesis

Null hypothesis: \mu =0

Alternative hypothesis: \mu \neq 0

The reason is because the output says a bilateral test so for this case w eselect this option.

b) Identify the statistic

The correct formula for the statistic is given by:

t=\frac{\bar X_1 -\bar X_2 -0}{\sqrt{(\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2})}}

Based on the output the calculated value its t =-7.44

c) Identify the p value

We have the degrees of freedom given 98

Based on the alternative hypothesis the p value is given by:

p_v = 2*P(t_{98}

d) State the final conclusion that addresses the original claim

Reject Null hypothesis. The is enough evidence to conclude that the mean prediction error is not equal to 0.

We reject the null hypothesis because the p_v. So we can conclude that the difference is significantly different from 0 at 5% of significance.

4 0
3 years ago
Use a table of values with at least 5 values to graph the following function:
34kurt

The given expression :

y=(\frac{1}{2})^x

For coordinates:

put x = 0 then :

\begin{gathered} y=(\frac{1}{2})^0 \\ y=1 \end{gathered}

Coordinate : (x, y) = (0, 1)

Put x= 1 and simplify :

\begin{gathered} y=(\frac{1}{2})^1 \\ y=\frac{1}{2} \\ y=0.5 \end{gathered}

Coordinate : (x, y) = ( 1, 0.5)

Put x = (-2) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-2} \\ y=\frac{1^{-2}}{2^{-2}} \\ y=\frac{2^2}{1^2} \\ y=2^2 \\ y=4 \end{gathered}

Coordinate : (x, y) = ( -2, 4)

Put x = (-3) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-3} \\ y=\frac{1^{-3}}{2^{-3}} \\ y=\frac{2^3}{1^3} \\ y=2^3 \\ y=8 \end{gathered}

Coordinate : (x, y) = (-3, 8)

Substitute x = (-1) and simplify :

\begin{gathered} y=(\frac{1}{2})^x \\ y=(\frac{1}{2})^{-1} \\ y=\frac{1^{-1}}{2^{-1}} \\ y=\frac{2}{1} \\ y=2 \end{gathered}

Coordinate : (x, y) = ( -1, 2)

So, the coordinates are :

The graph is :

4 0
2 years ago
Point (3,2) lies on the line ax+2y = 10. Find a. ​
polet [3.4K]

Answer:

-2

Step-by-step explanation:

Using y=mx+c

ax+2y=10

Put y as subject of formula

2y= 10-ax

2y= -ax+10

using point (3,2)

2y= -ax+10

2(3)= -a(2)+10

6= -2a+10

Put a as subject of formula

-2a=10-6

-2a=4

a= 4/-2

a= -2

4 0
3 years ago
Read 2 more answers
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