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Nezavi [6.7K]
11 months ago
13

a couple has three children. assuming each child has an equal chance of being a boy or a girl, what is the probability that they

have at least one girl? a. 1 b. .125 c. .5 d. .875
Mathematics
1 answer:
yaroslaw [1]11 months ago
3 0

Answer:

d. 0.875

Step-by-step explanation:

Having at least 1 girl out of 3 children means that there can be 1, 2 or 3 girls out of the 3 children.

So having at lest 1 girl out of 3 children is the same as saying that all 3 children are not boys.

The probability that all 3 children are boys would be

chance that child 1 is a boy * chance that child 2 is a boy * chance that child 3 is a boy = 0.5 * 0.5 * 0.5 = 0.125

And the probability that NOT all 3 children are boys would be

100% - probability that all 3 children are boys = 1 - 0.125 = 0.875

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Step-by-step explanation:

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8 0
3 years ago
If AC is parallel to DE, find X
UNO [17]

Answer: x = 50

Concept:

Here, we need to know the idea of alternative interior angles and the angle sum theorem.

<u>Alternative interior angles</u> are angles that are formed inside the two parallel lines, and the values are equal.

The <u>angle sum theorem</u> implies that the sum of interior angles of a triangle is 180°

If you are still confused, please refer to the attachment below or let me know.

Step-by-step explanation:

<u>Given information:</u>

AC ║ DE

∠ABC = 85°

∠A = 135°

<u>Find the value of ∠BAC</u>

∠A + ∠BAC = 180° (Supplementary angle)

(135°) + ∠BAC = 180°

∠BAC = 45°

<u>Find the value of ∠BCA</u>

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(85°) + (45°) + ∠BCA = 180°

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<u>Find the value of x (∠EBC)</u>

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Since, ∠BCA = 50°

Therefore, ∠EBC = 50°

\Large\boxed{x=50}

Hope this helps!! :)

Please let me know if you have any questions

8 0
1 year ago
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