Answer:
The pattern is this: I create a function p(x) such that
p(1)=1
p(2)=1
p(3)=3
p(4)=4
p(5)=6
p(6)=7
p(7)=9
Therefore, trivially evaluating at x=8 gives:
p(8)= 420+(cos(15))^3 -(arccsc(0.304))^(e^56) + zeta(2)
Ok, I know this isn’t what you were looking for. Be careful, you must specify what type of pattern is needed, because the above satisfies the given constraints.
Step-by-step explanation:
It will jut be blank im guessing because if one is blank of one of one hundred it will just be blank
Answer:
Step-by-step explanation:
Without loss of generality, let 
and 
(follows tan(C)=2.4). In a right triangle, the tangent of an angle is equal to its opposite side divided by its adjacent side and the cosine of an angle is equal to its adjacent side divided by the hypotenuse.
We can use the Pythagorean Theorem (
, where 
is the hypotenuse) to solve for the hypotenuse:
Therefore, 
Answer:
see explanation
Step-by-step explanation:
For the ellipse
+ 
= 1
Then the vertices are (a, 0), (- a, 0) and (0, b), (0, - b)
Given
+ 
= 1
Then
a² = 4 ⇒ a = 2 and b² = 100 ⇒ b = 10
Hence the vertices are
(2, 0), (- 2, 0) and (0, 10), (0, - 10)
