The area of the whole pizza must be at most 113.10 square inches in order to perfectly fit in the box. The values of r represent the half of the length of the pizza with respect to its center. In this case, the r must not exceed 6 inches (r ≤ 6 inches) in order to fit in the pizza box. On the other hand, the values of a represent the total area the pizza will occupy. In this case, the a must not exceed 113.10 square inches (a <span>≤ 113.10) </span>in order to house the pizza perfectly.
BE is congruent to overline CF since they are altitudes of the same trapezoid(S).
AB is congruent to overline CD (Given)
AE is congruent to overline FD by the Hypotenuse Leg Theorem.
triangle ABC is congruent to triangle DCF (SSS Triangle Congruence)
angle A is congruent to angle D since corresponding parts of congruent triangles are congruent.
Pemdas
ok if we look at the first one
exponents first
2^3=8
2^3=8
we have
4*8/8
4*8=32
32/8=4
das is answer
the first one is the answer
X=25 and y=-2 so then y=-40 and x=? you will have to divide and and multiple and the answer will be x=500
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:
And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
