Answer:
n = 0.0814 mol
Explanation:
Given mass, m = 35.7g
The molar mass of Tin(IV) bromate, M = 438.33 g/mol
We need to find the number of moles of bromine. We know that,
No. of moles = given mass/molar mass
So,
So, there are 0.0814 moles of bromine in 35.7g of Tin(IV) bromate.
Answer:
0.0125mol
Explanation:
Molarity (M) = number of moles (n) ÷ volume (V)
n = Molarity × Volume
According to this question, a 0.05M solution contains 250 mL of NaOH. The volume in litres is as follows:
1000mL = 1L
250mL = 250/1000
= 0.250L
n = 0.05 × 0.250
n = 0.0125
The number of moles of NaOH is 0.0125mol.
Answer:
11.74
Explanation:
The formula to find the pH of a solution is..
pH = -log [H⁺]
pH = -log [1.8×10¹²]
pH = 11.74
The answer would be to 2 decimal places because the concentration is two significant digits.
160gof CO2×1molof CO2\44g of CO2×1mole of C\1mol of CO2×12g of C\1mole of C=
43.63g of C
A. iron(III) oxide + Carbon-monoxide -> Iron + Carbon-di-oxide.
b.56*2 +16*3
c.Moles=mass(g) / Mr which is 3200/160
d. 2 moles
e.2 moles
f. Moles x Mr = mass so, 20 x 112=2240g
