Answer:
- Between 0 and 0.5 second the ball rises 16 feet, but between 0.5 and 1 second it rises only 8 more feet
- The ball rises by 16 in the first half second, but only 8 feet over the next one
- After it reaches 25 feet in the air, the ball drops
- The height of the ball above ground gets larger until 1.25 seconds and then gets smaller after that time.
Step-by-step explanation:
Let's rewrite the table:
Time (seconds) Height (feet)
0 0
0.5 16
1 24
1.25 25
1.5 24
2 16
2.5 0
By simply looking at the table, we can see that the following statements are all correct:
- Between 0 and 0.5 second the ball rises 16 feet, but between 0.5 and 1 second it rises only 8 more feet
- The ball rises by 16 in the first half second, but only 8 feet over the next one
- After it reaches 25 feet in the air, the ball drops
- The height of the ball above ground gets larger until 1.25 seconds and then gets smaller after that time.
Answer:
f^-1(x)=1/5x-2
Step-by-step explanation:
f(x) = 5x + 10
Use substitution
y = 5x + 10
Interchange the variables
x = 5y + 10
Swap the sides
5y + 10 = x
Move the constant to the right
5y = x - 10
Divide both sides
y = 1/5x-2
Use substitution
f^-1(x)=1/5x-2
Final Answer
Hope this helped!
Answer:
![\frac{3x + 2}{x + 1}](https://tex.z-dn.net/?f=%5Cfrac%7B3x%20%2B%202%7D%7Bx%20%2B%201%7D)
Step-by-step explanation:
![\frac{6x^{2} + x - 2}{2x^{2} + x - 1}](https://tex.z-dn.net/?f=%5Cfrac%7B6x%5E%7B2%7D%20%2B%20x%20-%202%7D%7B2x%5E%7B2%7D%20%2B%20x%20-%201%7D)
first, factor each polynomial expression:
![\frac{(3x + 2)(2x - 1)}{(x + 1)(2x - 1)}](https://tex.z-dn.net/?f=%5Cfrac%7B%283x%20%2B%202%29%282x%20-%201%29%7D%7B%28x%20%2B%201%29%282x%20-%201%29%7D)
then, the (2x - 1) from the top and the bottom cancel each other out. so the final answer should be:
![\frac{3x + 2}{x + 1}](https://tex.z-dn.net/?f=%5Cfrac%7B3x%20%2B%202%7D%7Bx%20%2B%201%7D)
Answer:
c
Step-by-step explanation: