Step-by-step explanation:
LHS=(1-sin60)/cos60
=(1-√3÷2)/1÷2
=2(1-√3÷2)
=2-√3
RHS=(1-tan30)/(1+tan30)
={1-(1÷√3)}/{1+(1÷√3)}
={(√3-1)/√3}/{(√3+1)/√3}
=(√3-1)/(√3+1)
={(√3-1)(√3-1)}/{(√3+1)(√3-1)}
=(3-√3-√3+1)/(3-1)
=(4-2√3)/2
=2-√3
Therefore LHS=RHS
Answer:
Depth = 3.3 inches
Step-by-step explanation:
Given that the shape of the satellite looks like a parabola
The equation of parabola is given as follows

Where
a= 13
Therefore


Lets take (13 , y) is a
Now by putting the values in the above equation we get


y=3.25 in
Therefore the depth of the satellite at the nearest integer will be 3.3 inches.
Depth = 3.3 inches
Number 3 is 1:3 but I don't know what 4 is I can't see the whole problem
I believe it is congruent